Find Coefficients in y=-x² + 3x + 40: Quadratic Equation Analysis

Question

Identify the coefficients based on the following equation

y=x2+3x+40 y=-x^2+3x+40

Video Solution

Solution Steps

00:00 Find the function coefficients
00:03 We'll use the formula to represent a quadratic equation
00:12 We'll separate the variable from the coefficient
00:29 We'll compare the formula to our equation and find the coefficients
00:43 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the given quadratic equation and its form.
  • Step 2: Directly match the coefficients of the given equation to the standard form y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Compare with the provided choices and select the one that matches.

Now, let's work through each step:
Step 1: The given quadratic equation is y=x2+3x+40 y = -x^2 + 3x + 40 . This matches the form y=ax2+bx+c y = ax^2 + bx + c .

Step 2: By comparing the given equation to the standard form:
- The coefficient a a is the coefficient of x2 x^2 , which is 1-1.
- The coefficient b b is the coefficient of x x , which is 3 3 .
- The coefficient c c is the constant term, which is 40 40 .

Step 3: From the analysis, we identify a=1 a = -1 , b=3 b = 3 , c=40 c = 40 . We compare these with the provided choices.
The correct answer is: a=1,b=3,c=40 a=-1,b=3,c=40

Therefore, the solution to the problem matches choice 4.

Answer

a=1,b=3,c=40 a=-1,b=3,c=40