Find Increasing Intervals for y = -(x-14)^2 - 6: Vertex Form Quadratic

To solve this problem, we need to determine where the function $y = -(x-14)^2 - 6$ is increasing.

Step 1: Notice that the given function is in the form $y = a(x-h)^2 + k$, which indicates it is a quadratic function.

Step 2: The coefficient $a = -1$, so the parabola opens downwards. This implies the function decreases to the left of the vertex and increases to the right.

Step 3: Identify the vertex of the parabola. The vertex form is $(h, k)$, where $h = 14$ and $k = -6$. Thus, the vertex is at $(14, -6)$.

Step 4: For a downward-opening parabola, the function is increasing on the left side of the vertex. Hence, the function is increasing for $x < 14$.

Therefore, the intervals where the function is increasing is $x < 14$.

The correct answer is: $\textbf{x < 14}$.