Find Increasing Intervals for the Quadratic Function y = (x+8)² - 1

To solve this problem of finding where the function $y=(x+8)^2-1$ is increasing, we will follow these steps:

• Identify the vertex: The function is in vertex form $y = (x+8)^2 - 1$. Therefore, the vertex is at $(h, k) = (-8, -1)$.
• Determine the direction of opening: Since the coefficient of $(x+8)^2$ is positive (1), the parabola opens upwards.
• Find intervals of increase: For an upward-opening parabola, the function increases to the right of the vertex. Therefore, the function is increasing for $x > -8$.

Thus, the interval where the function is increasing is $x > -8$.