Find Intervals of Increase and Decrease: y = -4√7x² Quadratic Function

Find the intervals of increase and decrease of the function:
y=47x2 y=-4\sqrt{7}x^2

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1

Understand the problem

Find the intervals of increase and decrease of the function:
y=47x2 y=-4\sqrt{7}x^2

2

Step-by-step solution

The function is given by y=47x2 y = -4\sqrt{7}x^2 , which is a downward-opening parabola because the coefficient a=47 a = -4\sqrt{7} is negative.

The vertex of the parabola is at the origin (0,0). A downward-opening parabola decreases as x x moves away from the vertex in the positive x x -direction, and increases as x x moves away from the vertex in the negative x x -direction.

Thus, the intervals of increase and decrease for this function are:

  • The function increases on the interval (,0) (-\infty, 0) .
  • The function decreases on the interval (0,) (0, \infty) .

Therefore, the intervals of increase and decrease can be denoted as:

:x>0:x<0 \searrow:x>0\\\nearrow:x<0

3

Final Answer

:x>0:x<0 \searrow:x>0\\\nearrow:x<0

Practice Quiz

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Note that the graph of the function shown below does not intersect the x-axis

The parabola's vertex is A

Identify the interval where the function is decreasing:

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