Determine the points of intersection of the function
With the X
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Determine the points of intersection of the function
With the X
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We start by setting the equation to zero:
.
Step 2: Using the zero-product property, we find:
1.
2.
Step 3: Solve each of these equations for :
For , subtract 8 from both sides to get . Divide both sides by 4, resulting in:
.
For , subtract 1 from both sides to get:
.
Thus, the points of intersection of the function with the x-axis are the solutions we just found. At these points, the y-value is zero, giving us the intersection points as and .
Therefore, the solution to the problem is .
The following function has been graphed below:
\( f(x)=-x^2+5x+6 \)
Calculate points A and B.
X-intercepts are points where the graph crosses the x-axis. At these points, the y-coordinate is always zero. So we set y = 0 to find where the function equals zero!
You'd need to factor the quadratic first before using the zero product property. Expand to get , then factor it back.
Intersection points are coordinates with both x and y values. Since we're finding x-intercepts, the y-coordinate is always 0, giving us points like (-1, 0) and (-2, 0).
Yes, but it's much harder! Since the function is already factored, using the zero product property is the fastest method. Save the quadratic formula for when factoring is difficult.
Solve each factor separately: gives , and gives . Both are equally valid solutions!
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