Determine Intersection Points of y = (x + 8)(x - 9) on the X-Axis

Determine the points of intersection of the function

$y=(x+8)(x-9)$

With the X

The solution to the problem involves finding the x-intercepts of the given quadratic function, which are the points where the function intersects the x-axis (i.e., where $y = 0$).

Step by step solution:

• Set the function equal to zero: $(x+8)(x-9) = 0$.
• The product of two terms is zero if and only if at least one of the terms is zero. Therefore, we solve:
  $x+8 = 0$ or $x-9 = 0$.
• For $x+8 = 0$:
  Subtract 8 from both sides to isolate $x$:
  $x = -8$.
• For $x-9 = 0$:
  Add 9 to both sides to isolate $x$:
  $x = 9$.

The function intersects the x-axis at the points $(-8, 0)$ and $(9, 0)$.

Therefore, the points of intersection of the function with the x-axis are $(-8, 0)$ and $(9, 0)$.