Finding the Symmetry Point of the Quadratic Function f(x) = 3 - 5x²

To find the symmetry point of the quadratic function $f(x) = 3 - 5x^2$, we follow these steps:

• Identify that the function is in the form $f(x) = ax^2 + bx + c$, where $a = -5$, $b = 0$, and $c = 3$.

• The x-coordinate of the symmetry point, also known as the vertex, is given by the formula $x = -\frac{b}{2a}$.

• Substitute the values: $x = -\frac{0}{2(-5)} = 0$.

• Calculate the y-coordinate by substituting $x = 0$ into the function: $f(0) = 3 - 5(0)^2 = 3$.

• Hence, the symmetry point of the function is $(0, 3)$.

Therefore, the symmetry point of the function $f(x) = 3 - 5x^2$ is $(0, 3)$.