Finding X: Determine When y=5x² is Greater Than Zero

Given the function:

$y=5x^2$

Determine for which values of x $f\left(x\right) > 0$ holds

The given function is $y = 5x^2$. This is a quadratic function where the coefficient of $x^2$ is positive, making the parabolic shape open upwards.

The expression $5x^2$ is always non-negative. For this function to be greater than zero, it should not be equal to zero. We find the expression equals zero when $x = 0$.

When $x \neq 0$, $5x^2$ is positive. Therefore, $y = 5x^2 > 0$ whenever $x \neq 0$. This applies to both positive and negative $x$ values, except for zero.

Thus, the correct answer is: $x \neq 0$.