Determine x-Values for the Quadratic: y = 3/4x² < 0

To solve this problem, we'll consider the given quadratic function $y = \frac{3}{4}x^2$ and analyze when it could be negative.

Let's break this down:

• The expression $x^2$ represents the square of $x$, which is always non-negative for any real number $x$.
• Since the coefficient of $x^2$, which is $\frac{3}{4}$, is positive, multiplying $x^2$ by this constant results in a non-negative value.

Combining these observations:

• Since $x^2 \geq 0$ for all $x$, it follows that $\frac{3}{4}x^2 \geq 0$ for all $x$.
• Thus, the function $y = \frac{3}{4}x^2$ will always be non-negative, meaning it can never be less than zero.

Therefore, there are no values of $x$ for which $f(x) < 0$.

Based on this analysis, the correct answer is that there are No $x$ for which the expression is negative.