Identify the Domain of the Function: Issues with 1/(5x - 4)

Function Domains with Rational Expressions

Look the following function:

15x4 \frac{1}{5x-4}

What is the domain of the function?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Does the function have a domain? And if so, what is it?
00:04 To find the domain, remember that division by 0 is not allowed
00:07 So let's see what solution zeros the denominator
00:13 Let's isolate X
00:31 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look the following function:

15x4 \frac{1}{5x-4}

What is the domain of the function?

2

Step-by-step solution

To determine the domain of the function 15x4 \frac{1}{5x-4} , we need to find the values of x x for which the function is undefined. This occurs when the denominator equals zero:

First, set the denominator equal to zero:
5x4=0 5x - 4 = 0

Next, solve for x x :
5x=4 5x = 4
x=45 x = \frac{4}{5}

The function is undefined at x=45 x = \frac{4}{5} . Therefore, the domain of the function includes all real numbers except x=45 x = \frac{4}{5} .

In mathematical notation, the domain is:
x45 x \ne \frac{4}{5} .

This matches choice 3 among the given options.

3

Final Answer

x45 x\ne\frac{4}{5}

Key Points to Remember

Essential concepts to master this topic
  • Domain Rule: Function undefined when denominator equals zero
  • Technique: Set 5x - 4 = 0, solve: x = 4/5
  • Check: Substitute back: 5(4/5) - 4 = 4 - 4 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Setting the numerator equal to zero instead of denominator
    Don't set the numerator (1) equal to zero = wrong restriction! The numerator being zero makes the function equal zero, not undefined. Always set the denominator equal to zero to find where the function is undefined.

Practice Quiz

Test your knowledge with interactive questions

\( \frac{6}{x+5}=1 \)

What is the field of application of the equation?

FAQ

Everything you need to know about this question

Why can't the denominator be zero?

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Division by zero is undefined in mathematics! When the denominator equals zero, the fraction 15x4 \frac{1}{5x-4} has no meaning, so these x-values must be excluded from the domain.

How do I write the domain properly?

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You can write it as x45 x \ne \frac{4}{5} or as interval notation: (,45)(45,) (-\infty, \frac{4}{5}) \cup (\frac{4}{5}, \infty) . Both show that x cannot equal 4/5.

What if there are multiple terms in the denominator?

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Set the entire denominator equal to zero and solve. For example, with 1x24 \frac{1}{x^2-4} , solve x24=0 x^2-4=0 to get x = ±2.

Can the domain ever include all real numbers?

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Yes! If the denominator is never zero (like 1x2+1 \frac{1}{x^2+1} ), then the domain includes all real numbers since x2+1 x^2+1 is always positive.

Do I need to simplify fractions in my final answer?

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Always simplify! If you get x=810 x = \frac{8}{10} , reduce it to x=45 x = \frac{4}{5} . This matches the standard form and prevents confusion.

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