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To solve this arithmetic problem using long division, we will divide 831 by 2.
Let's perform the steps:
The quotient is 415 and the remainder is 1.
Therefore, the solution to the problem is with a remainder of 1.
with a remainder of 1
In long division, we work from left to right because we're finding the largest place value first. Starting with 8 (hundreds place) gives us 4 in the hundreds place of our answer.
That's when you get a remainder! Like when 3 ÷ 2 = 1 remainder 1. Write down the 1 as your quotient digit, then bring down the next digit to combine with your remainder.
You always bring down the next digit after completing each division step. In 831 ÷ 2, after dividing 8, bring down the 3. After dividing 3, bring down the 1.
That's your final remainder! Write it as 'remainder [number]' like we got 415 remainder 1. This means 831 doesn't divide evenly by 2.
Use this formula: quotient × divisor + remainder = original number. For our problem: 415 × 2 + 1 = 830 + 1 = 831 ✓
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