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To solve the problem, we will perform a long division of 816 by 5.
Let's go through the steps of long division:
This implies the complete division yields a quotient of 163 with a remainder of 1.
Therefore, the solution to the problem is with a remainder of 1.
with a remainder of 1
Bringing down means writing the next digit of the dividend next to your remainder. For example, after getting remainder 3 from 8 ÷ 5, you bring down the '1' to make '31' for the next division step.
Stop when you've used all digits from the original number (816). The final remainder (if any) becomes part of your answer. In this case, we used all three digits and got remainder 1.
If 8 were smaller than 5, you'd look at the first two digits together. But since 8 > 5, we can divide right away and get 1 with remainder 3.
The remainder is what's left after the final division step. We had 16 ÷ 5 = 3 with 1 left over. The remainder must always be smaller than the divisor (5).
Yes! Use this formula: quotient × divisor + remainder = original number. So: ✓
If there's no remainder, the division is exact and you just write the quotient. For example, 820 ÷ 5 = 164 with no remainder needed.
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