Long Division Problem: Divide 816 by 5

Long Division with Three-Digit Dividends

5816

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:04 Let's solve this problem together!
00:07 Start by dividing the first digit of the dividend.
00:11 Write the answer on top, leaving out any remainder.
00:16 Next, multiply that answer by the divisor.
00:19 Subtract the result from your number.
00:23 Bring down the next digit, and repeat.
00:26 Divide again. You've got this!
00:30 Write your answer above, in the correct spot.
00:34 Multiply your answer by the divisor, and subtract.
00:42 Bring down the next digit, and keep going.
00:45 Divide once more. Almost there!
00:51 Carefully write your answer above, in place.
00:58 Multiply, and subtract. You're doing great!
01:04 We have a remainder of 1.
01:09 And that's how we solve the problem. Well done!

Step-by-step written solution

Follow each step carefully to understand the complete solution
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Understand the problem

5816

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Step-by-step solution

To solve the problem, we will perform a long division of 816 by 5.

Let's go through the steps of long division:

  • Step 1: Divide the first digit of the dividend: 8÷5=1 8 \div 5 = 1 . The quotient so far is 1.
  • Step 2: Multiply 1 (quotient) by 5 (divisor) to get 5.
  • Step 3: Subtract 5 from 8 which gives a remainder of 3. Bring down the next digit (1) to make it 31.
  • Step 4: Divide 31 by 5. 31÷5=6 31 \div 5 = 6 remainder 1. The quotient now is 16.
  • Step 5: Multiply 6 (newest quotient digit) by 5 to get 30.
  • Step 6: Subtract 30 from 31 which leaves a remainder of 1. Bring down the last digit (6) of the original number to make it 16.
  • Step 7: Divide 16 by 5. 16÷5=3 16 \div 5 = 3 remainder 1. Add 3 to the quotient making it 163.
  • Step 8: Multiplying 3 by 5, we get 15.
  • Step 9: Subtract 15 from 16 to get a final remainder of 1.

This implies the complete division yields a quotient of 163 with a remainder of 1.

Therefore, the solution to the problem is 163 163 with a remainder of 1.

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Final Answer

163 163 with a remainder of 1

Key Points to Remember

Essential concepts to master this topic
  • Rule: Work left to right, dividing each place value systematically
  • Technique: Bring down next digit when remainder exists: 31 ÷ 5 = 6 remainder 1
  • Check: Multiply quotient by divisor and add remainder: 163 × 5 + 1 = 816 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to bring down the next digit
    Don't leave remainders hanging without bringing down the next digit = incomplete division! This stops the process too early and gives a wrong quotient. Always bring down each digit systematically to continue the division until all digits are used.

Practice Quiz

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216

FAQ

Everything you need to know about this question

What does 'bring down' mean in long division?

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Bringing down means writing the next digit of the dividend next to your remainder. For example, after getting remainder 3 from 8 ÷ 5, you bring down the '1' to make '31' for the next division step.

How do I know when to stop dividing?

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Stop when you've used all digits from the original number (816). The final remainder (if any) becomes part of your answer. In this case, we used all three digits and got remainder 1.

What if the first digit is smaller than the divisor?

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If 8 were smaller than 5, you'd look at the first two digits together. But since 8 > 5, we can divide right away and get 1 with remainder 3.

Why is the remainder 1 and not something else?

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The remainder is what's left after the final division step. We had 16 ÷ 5 = 3 with 1 left over. The remainder must always be smaller than the divisor (5).

Can I check my answer without doing the whole division again?

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Yes! Use this formula: quotient × divisor + remainder = original number. So: 163×5+1=815+1=816 163 × 5 + 1 = 815 + 1 = 816

What happens if there's no remainder?

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If there's no remainder, the division is exact and you just write the quotient. For example, 820 ÷ 5 = 164 with no remainder needed.

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