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To solve this problem, we'll use the long division method to divide by :
1. Consider the first digit of the dividend, . How many times does go into ? It fits 1 time.
2. Write in the quotient and subtract from the digit to get . Next, bring down the next digit, which is , making the number .
3. Determine how many times fits into . It fits no times, so write in the quotient, resulting in in the quotient so far. Bring down the next digit , making it .
4. How many times does go into ? It fits 10 times. Write a in the quotient next to the existing one, making .
5. Subtract , resulting in . Bring down the next digit , making it .
6. How many times does go into ? It fits 2 times. Write in the quotient, yielding a final quotient of .
Subtract from , resulting in a remainder of , indicating division is complete with no remainder.
Therefore, the quotient when is divided by is .
After the first division step, you have remainder 0 and bring down the next 7. Since 7 goes into 7 exactly once, you might think to write 1. But you already used that first 7! The new 7 in position represents 70s, and 7 goes into 7 (in the 10s place) zero times.
Place value is crucial! Start from the leftmost digit of the dividend. Each quotient digit goes directly above the corresponding dividend digit you're working with. Never skip positions!
Always work left to right through the dividend. After each division step, bring down the very next digit that hasn't been used yet. Write it next to your remainder to form the new number to divide.
Multiply your quotient by the divisor: . If you get back to , your answer is correct! This is the best way to verify long division.
A remainder of 0 means the division is exact - the dividend divides evenly by the divisor with no leftover amount. This makes a perfect division!
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