Multiply (a+b+2c)(3a-2b): Expanding Two-Factor Polynomial Expression

Polynomial Expansion with Mixed Variables

Solve:

(a+b+2c)(3a2b)= (a+b+2c)\cdot(3a-2b)=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solution
00:04 Open parentheses properly, multiply each factor by each factor
00:43 Calculate the multiplications
01:22 Positive times negative always equals negative
01:40 Collect terms
01:49 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve:

(a+b+2c)(3a2b)= (a+b+2c)\cdot(3a-2b)=

2

Step-by-step solution

To solve the expression (a+b+2c)(3a2b)(a+b+2c)\cdot(3a-2b), we will apply the distributive property.

  • Step 1: Distribute each term of the first expression to every term of the second expression.

  • Step 2: Compute the resulting products.

  • Step 3: Combine like terms.

Let's execute these steps:
Step 1: Distribute:
Distribute aa: a3a+a(2b)=3a22aba \cdot 3a + a \cdot (-2b) = 3a^2 - 2ab
Distribute bb: b3a+b(2b)=3ab2b2b \cdot 3a + b \cdot (-2b) = 3ab - 2b^2
Distribute 2c2c: 2c3a+2c(2b)=6ac4bc2c \cdot 3a + 2c \cdot (-2b) = 6ac - 4bc

Step 2: Add all these products together:
3a22ab+3ab2b2+6ac4bc3a^2 - 2ab + 3ab - 2b^2 + 6ac - 4bc

Step 3: Combine like terms:
Combine 2ab+3ab -2ab + 3ab to get ab ab.

Therefore, the simplified expression is:
3a2+ab2b2+6ac4bc3a^2 + ab - 2b^2 + 6ac - 4bc.

The correct choice is 4.

Thus, the final expanded expression is 3a2+ab2b2+6ac4bc3a^2 + ab - 2b^2 + 6ac - 4bc.

3

Final Answer

3a2+ab2b2+6ac4bc 3a^2+ab-2b^2+6ac-4bc

Key Points to Remember

Essential concepts to master this topic
  • Distribution: Apply each term in first polynomial to all terms in second
  • Technique: a3a=3a2 a \cdot 3a = 3a^2 and 2ab+3ab=ab -2ab + 3ab = ab
  • Check: Count terms: 5 original products should give 5 final terms ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute all terms completely
    Don't just multiply first terms together = 3a2 3a^2 only! This misses most of the expansion and gives incomplete results. Always multiply every term in the first polynomial by every term in the second polynomial.

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

How many terms should I get when expanding?

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When expanding (a+b+2c)(3a2b) (a+b+2c)(3a-2b) , you get 3 terms × 2 terms = 6 products before combining like terms. After combining, you'll have fewer terms.

Why do I need to combine like terms?

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Combining like terms simplifies your answer! For example, 2ab+3ab=ab -2ab + 3ab = ab . This gives you the final simplified form that's easier to work with.

What if I get confused with the signs?

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Take it one distribution at a time! Write out each step: a3a=3a2 a \cdot 3a = 3a^2 , then a(2b)=2ab a \cdot (-2b) = -2ab . Keep track of positive and negative signs carefully.

How do I know which terms are like terms?

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Like terms have the exact same variables with the same exponents. For example, 2ab -2ab and 3ab 3ab are like terms, but 3a2 3a^2 and ab ab are not.

Can I multiply polynomials in any order?

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Yes! Multiplication is commutative, so (a+b+2c)(3a2b) (a+b+2c)(3a-2b) gives the same result as (3a2b)(a+b+2c) (3a-2b)(a+b+2c) . Choose whichever order feels easier for you!

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