Multiply Square Roots: √1 × √2 × √3 Solution Guide

Solve the following exercise:

123= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's simplify this expression step by step.
00:12 The square root of number A, multiplied by the square root of number B, equals the square root of A times B.
00:19 We use this formula to solve our exercise and change it to a single root.
00:25 Now, let’s calculate our products carefully.
00:28 This is how we find the solution.

Step-by-step written solution

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1

Understand the problem

Solve the following exercise:

123= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for exponents applied to terms in parentheses (in reverse order):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a':

123112212312= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3} \\ \downarrow\\ 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}=

Due to the fact that there is a multiplication operation between three terms with identical exponents, we are able to apply the law of exponents mentioned in b' (which also applies to multiplication of several terms in parentheses) Combine them together in a multiplication operation within parentheses that are also raised to the same exponent:

112212312=(123)12=612=6 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}= \\ (1\cdot2\cdot3)^{\frac{1}{2}}=\\ 6^{\frac{1}{2}}=\\ \boxed{\sqrt{6}}

In the final steps, we performed the multiplication within the parentheses and once again used the definition of root as an exponent mentioned in a' (in reverse order) to return to root notation.

Therefore, the correct answer is answer d.

3

Final Answer

6 \sqrt{6}

Practice Quiz

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Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

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