Multiply Square Roots: √1 × √2 × √3 Solution Guide

Radical Multiplication with Product Property

Solve the following exercise:

123= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's simplify this expression step by step.
00:12 The square root of number A, multiplied by the square root of number B, equals the square root of A times B.
00:19 We use this formula to solve our exercise and change it to a single root.
00:25 Now, let’s calculate our products carefully.
00:28 This is how we find the solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

123= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for exponents applied to terms in parentheses (in reverse order):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a':

123112212312= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3} \\ \downarrow\\ 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}=

Due to the fact that there is a multiplication operation between three terms with identical exponents, we are able to apply the law of exponents mentioned in b' (which also applies to multiplication of several terms in parentheses) Combine them together in a multiplication operation within parentheses that are also raised to the same exponent:

112212312=(123)12=612=6 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}= \\ (1\cdot2\cdot3)^{\frac{1}{2}}=\\ 6^{\frac{1}{2}}=\\ \boxed{\sqrt{6}}

In the final steps, we performed the multiplication within the parentheses and once again used the definition of root as an exponent mentioned in a' (in reverse order) to return to root notation.

Therefore, the correct answer is answer d.

3

Final Answer

6 \sqrt{6}

Key Points to Remember

Essential concepts to master this topic
  • Product Property: ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} for multiplying square roots
  • Technique: Convert 123 \sqrt{1} \cdot \sqrt{2} \cdot \sqrt{3} to 123=6 \sqrt{1 \cdot 2 \cdot 3} = \sqrt{6}
  • Check: Calculate (6)2=6 (\sqrt{6})^2 = 6 and verify 123=6 1 \cdot 2 \cdot 3 = 6

Common Mistakes

Avoid these frequent errors
  • Multiplying the numbers under the radicals directly without using the product property
    Don't calculate √1 = 1, √2 ≈ 1.414, √3 ≈ 1.732 then multiply = 2.449! This gives a decimal instead of the exact radical form. Always use the product property: √1 × √2 × √3 = √(1×2×3) = √6.

Practice Quiz

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Choose the largest value

FAQ

Everything you need to know about this question

Why is √6 better than calculating the decimal approximation?

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The exact answer √6 is preferred because it's the exact value! Decimal approximations like 2.449 are rounded and less precise than the radical form.

Can I use the product property with more than two square roots?

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Yes! The product property works for any number of square roots: abc=abc \sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} = \sqrt{a \cdot b \cdot c} . Just multiply all the numbers under one radical sign.

What if one of the numbers under the square root is 1?

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Remember that √1 = 1, so it doesn't change the calculation. In our problem: 123=123=23=6 \sqrt{1} \cdot \sqrt{2} \cdot \sqrt{3} = 1 \cdot \sqrt{2} \cdot \sqrt{3} = \sqrt{2 \cdot 3} = \sqrt{6}

How do I know when to leave an answer as a radical?

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Leave your answer as a radical like √6 when it cannot be simplified further. Since 6 = 2×3 has no perfect square factors other than 1, √6 is already in simplest form.

Can I check my answer without a calculator?

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Yes! Square both sides: (6)2=6 (\sqrt{6})^2 = 6 and (123)2=123=6 (\sqrt{1} \cdot \sqrt{2} \cdot \sqrt{3})^2 = 1 \cdot 2 \cdot 3 = 6 . Since both equal 6, √6 is correct!

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