Multiply Square Roots: Calculate √10 × √2 × √5

Square Root Multiplication with Three Terms

Solve the following exercise:

10⋅2⋅5= \sqrt{10}\cdot\sqrt{2}\cdot\sqrt{5}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's simplify this expression together.
00:12 The square root of Number A times the square root of Number B.
00:18 Is equal to the square root of A times B.
00:22 Now, use this rule to convert both roots to a single root.
00:27 Let's calculate those products now. You're doing great!
00:39 Change 100 to 10 to the power of two.
00:44 And that's the solution! Excellent work.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

10⋅2⋅5= \sqrt{10}\cdot\sqrt{2}\cdot\sqrt{5}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for an exponent applied to a product in parentheses (in reverse direction):

xn⋅yn=(x⋅y)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a:

10⋅2⋅5↓1012⋅212⋅512= \sqrt{10}\cdot\sqrt{2}\cdot\sqrt{5} \\ \downarrow\\ 10^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot5^{\frac{1}{2}}=

Due to the fact that there is a multiplication operation between three terms with identical exponents we are able to apply the law of exponents mentioned in b (which also applies to multiplying several terms in parentheses) Combine them together in a multiplication operation within parentheses, which are also raised to the same exponent:

1012⋅212⋅512=(10⋅2⋅5)12=10012=100=10 10^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot5^{\frac{1}{2}}= \\ (10\cdot2\cdot5)^{\frac{1}{2}}=\\ 100^{\frac{1}{2}}=\\ \sqrt{100}=\\ \boxed{10}

In the final steps, we first performed the multiplication within the parentheses, we then once again used the definition of root as an exponent mentioned in a (in reverse direction) to return to root notation, and in the final stage we calculated the known square root of 100.

Therefore, we can identify that the correct answer (most appropriate) is answer d.

3

Final Answer

10 10

Key Points to Remember

Essential concepts to master this topic
  • Rule: Multiply square roots by combining under one radical
  • Technique: a⋅b=a⋅b \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} gives 10⋅2⋅5=100 \sqrt{10 \cdot 2 \cdot 5} = \sqrt{100}
  • Check: Verify by computing the product inside: 10 × 2 × 5 = 100, so 100=10 \sqrt{100} = 10 ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of multiplying the numbers under the radicals
    Don't add 10 + 2 + 5 = 17 and write 17 \sqrt{17} ! This ignores the multiplication between the square roots and gives the wrong answer. Always multiply the numbers under the radicals: 10 × 2 × 5 = 100.

Practice Quiz

Test your knowledge with interactive questions

Choose the largest value

FAQ

Everything you need to know about this question

Why can I multiply numbers under different square roots?

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The multiplication property of square roots states that a⋅b=a⋅b \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} . This works because both expressions equal the same value when simplified!

Do I have to convert to exponents like in the explanation?

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No! Converting to exponents helps understand why the rule works, but you can directly use 10⋅2⋅5=10⋅2⋅5 \sqrt{10} \cdot \sqrt{2} \cdot \sqrt{5} = \sqrt{10 \cdot 2 \cdot 5} for faster solving.

What if the product under the radical isn't a perfect square?

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Then you simplify as much as possible. For example, 72=36⋅2=62 \sqrt{72} = \sqrt{36 \cdot 2} = 6\sqrt{2} . Look for perfect square factors!

Can I use this rule with more than three square roots?

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Absolutely! The rule works for any number of square roots: a⋅b⋅c⋅d=a⋅b⋅c⋅d \sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} \cdot \sqrt{d} = \sqrt{a \cdot b \cdot c \cdot d}

How do I know when my final answer should be simplified?

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Always check if the number under the radical is a perfect square. If 100 \sqrt{100} , 49 \sqrt{49} , 25 \sqrt{25} , etc., simplify to the whole number!

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