If we have 226 blocks and we remove all of the tens and the ones, how many blocks will remain?
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If we have 226 blocks and we remove all of the tens and the ones, how many blocks will remain?
To solve the problem, we need to perform the following steps:
Step 1: In the number 226, the digit in the tens place is 2, which means there are 20 (2 tens), and the digit in the ones place is 6.
Step 2: The sum of the tens and ones is .
Step 3: Subtract this sum from the total number of blocks: .
Therefore, the calculation is .
The number of remaining blocks is 200.
Add fifty units to the number 31.
What is the resulting number?
In place value, each position represents a different power of 10. The digit 2 in the tens place means 2 groups of 10, which equals 20 blocks, not just 2 blocks.
It means taking away all the blocks represented by the tens place (20 blocks) and the ones place (6 blocks). So we remove 20 + 6 = 26 blocks total from our 226 blocks.
After removing the tens and ones, only the hundreds place remains. Since 226 has 2 in the hundreds place, we're left with 2 hundreds = 200 blocks.
Think of 226 as 2 hundred-squares + 2 ten-rods + 6 unit-cubes. Remove the 2 ten-rods and 6 unit-cubes, and you're left with just the 2 hundred-squares = 200.
Yes! Since we're removing tens and ones, we can think: what's left is just the hundreds. In 226, that's 200. But always double-check: 226 - 26 = 200 ✓
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