If in total we have 545 blocks,
and we only remove the hundreds and ones, write down the resulting exercise:
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If in total we have 545 blocks,
and we only remove the hundreds and ones, write down the resulting exercise:
To solve this problem, we'll be removing the hundreds and ones digits from the total 545 blocks and writing the resulting subtraction exercise.
Therefore, the solution to the problem is .
If we have 67 blocks in total, how many blocks will remain if we remove 5 tens and 4 ones?
Because digits have different values depending on their position! The first 5 represents 500 (5 hundreds), while the last 5 represents just 5 (5 ones). You must consider place value when working with multi-digit numbers.
It means remove the value contributed by those place positions. In 545: hundreds place contributes 500, tens place contributes 40, ones place contributes 5. So removing hundreds and ones means subtracting 500 + 5 = 505.
Look at the visual representation: Large squares = hundreds, rectangular strips = tens, small squares = ones. Count each type separately to understand the place value breakdown.
After removing 500 (hundreds) and 5 (ones) from 545, only the tens place value remains. Since 545 has 4 in the tens place, 4 × 10 = 40 is what's left.
Use addition to verify: Add your answer back to what you removed. If 40 + 505 = 545, then your subtraction is correct!
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