Subtraction: Graphical representation

To solve this problem, we begin by calculating the total number of blocks to remove.

Step 1: Calculate the blocks in 4 tens.

• A "ten" refers to 10 blocks. Thus, 4 tens equal $4 \times 10 = 40$ blocks.

Step 2: Calculate the total blocks to remove by combining tens and ones.

• We are also removing 1 more block, so the total becomes $40 + 1 = 41$ blocks.

Step 3: Subtract the total removed blocks from the initial total to determine how many blocks remain.

• $85 - 41 = 44$.

Therefore, the number of blocks remaining is $44$.

To solve this problem, we'll perform basic subtraction.

• Step 1: Identify the minuend and subtrahend.

• The minuend (the number from which we are subtracting) is 85.

• The subtrahend (the number to be subtracted) is 30.

• Step 2: Apply the subtraction formula $85 - 30$.

• Step 3: Calculate the difference.

Subtract 30 from 85 as follows:
$85 - 30 = 55$

Therefore, the solution to the problem is $55$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information, which is the number 92 and the amount to subtract, 60.
• Step 2: Perform the subtraction operation: $92 - 60$.

Now, let's work through each step:

Step 1: We know we need to subtract 60 from 92. This can be expressed mathematically as $92 - 60$.

Step 2: Perform the subtraction:

$92 - 60 = 32$

We find that subtracting 60 from 92 yields 32.

Therefore, the solution to the problem is $32$.

To solve this problem, we'll proceed through the following steps:

• Step 1: Identify how many blocks are represented by "2 tens".
• Step 2: Subtract the number of removed blocks from the total number of blocks given.

Now, let's work through each step:
Step 1: "2 tens" equates to $2 \times 10 = 20$ blocks.
Step 2: We are removing 20 blocks from the total of 46 blocks. Using subtraction, we have:

Therefore, after removing 2 tens (which is 20 blocks), the number of blocks that remain is $26$.

To solve this simple subtraction problem, let's follow the steps:
Step 1: Identify the numbers involved, which are $73$ and $3$.
Step 2: Apply the operation of subtraction to these numbers. The problem asks us to subtract $3$ from $73$, resulting in the mathematical operation $73 - 3$.
Step 3: Calculate the result of the subtraction: $73 - 3 = 70$.

Therefore, the result of subtracting three units from the number 73 is $70$.

To determine how many blocks remain, follow these steps:

• Step 1: Calculate how many blocks 5 tens represent: $5 \times 10 = 50$.
• Step 2: Add the 4 individual blocks being removed: $50 + 4 = 54$.
• Step 3: Subtract the total removed blocks from the original number of blocks: $55 - 54 = 1$.

After performing these calculations, we find that the number of blocks remaining is $1$.

Therefore, the solution to the problem is $1$.

To solve this problem, we begin by determining what needs to be subtracted from the number 36. We have "2 tens" and "5 units" to subtract:

• 2 tens is equal to 20 because one ten is equal to 10.
• 5 units are simply the number 5 added directly.

Therefore, the total amount to subtract is $20 + 5 = 25$.

Next, we perform the subtraction operation:

Starting with the number 36, subtract 25:

• $36 - 25 = 11$

After performing the subtraction, we conclude that the final result is:

$11$.

To solve this problem, let's consider the following steps:

• Step 1: Understand the removal of blocks. We are removing 5 tens and 4 ones. One "ten" equals 10 units, so 5 tens equal $5 \times 10 = 50$ units.
• Step 2: Calculate the total number of blocks to be removed. We have 50 (from tens) + 4 (ones) = 54 units to be removed.
• Step 3: Perform the subtraction from the total number of blocks. The total number of blocks is 67. Therefore, we calculate $67 - 54 = 13$.

After performing the above calculations, we confirm that the number of blocks remaining is $13$.

Let's solve the problem step by step:

We begin with a total of $79$ blocks.

First, we need to determine how many blocks are removed:

• Two tens, which equals $2 \times 10 = 20$ blocks.
• Three ones, equaling $3$ blocks.

Add the blocks removed together: $20 + 3 = 23$ blocks removed in total.

Now, subtract the total blocks removed from the starting total:

Therefore, the number of blocks remaining is $56$.

To solve this problem, we will use simple subtraction, following these steps:

• Step 1: Identify the initial quantity of blocks, which is 17.

• Step 2: Identify the quantity to be removed, which is 7 blocks.

• Step 3: Perform the subtraction to find the remaining quantity of blocks:

$\begin{aligned} \text{Initial quantity} & = 17 \\ \text{Blocks removed} & = 7 \\ \text{Remaining quantity} & = 17 - 7 \end{aligned}$

By calculating $17 - 7$, we find that the remaining quantity is $10$.

Therefore, the solution to the problem is $10$.

To solve this problem, we will follow these straightforward steps:

• Identify the number from which we will subtract: this is the number 46.
• Identify the number to subtract: this is the number 6.
• Perform the subtraction operation: subtract 6 from 46.

Let's perform the subtraction:

$46 - 6$

Subtracting 6 from 46 involves the following:

• Determine the units: 6 subtracted from 6 leaves 0 in the units place.
• The tens place remains unaffected directly, as the operation is straightforward: 4 tens remain as 4 since the operation only affects the units.

So, the calculation becomes:

$46 - 6 = 40$

Therefore, after subtracting 6 from 46, the result is $40$.

To solve this problem, we'll follow these steps:

• Identify the numbers involved, which are 79 and 9.
• Use the subtraction operation to compute $79 - 9$.
• Verify the result for any potential errors.

Now, let's calculate the solution:
Step 1: We have been given the number 79, from which we need to subtract 9.
Step 2: The subtraction $79 - 9$ is calculated as follows:

Write it vertically to subtract:

$\ \begin{array}{c} 79 \\ - 9 \\ \hline \end{array}$

Subtract 9 from 9 in the ones place, resulting in 0 in the ones place.
Subtract 0 from 7 in the tens place, resulting in 7 in the tens place.

$\ \begin{array}{c} 79 \\ - 9 \\ \hline 70 \\ \end{array}$

Therefore, the correct answer is $70$.

Concluding the calculations, the subtraction of 9 from 79 yields the result of $70$.

To solve this problem, we will use simple subtraction. Here's how we can arrive at the answer:

• Step 1: Identify the initial number of blocks: $53$.
• Step 2: Identify the number of blocks to be removed: $3$.
• Step 3: Perform the subtraction: $53 - 3$.

Now, we will calculate:

$53 - 3 = 50$.

Therefore, after removing 3 blocks, the number of remaining blocks is $50$.

To solve this problem of how many units are left after removing 4 units from 34, we'll follow these steps:

• Step 1: Identify the initial amount and the number of units to remove, which are 34 and 4 respectively.
• Step 2: Apply the subtraction operation to find the remaining units.
• Step 3: Perform the subtraction to get the result.

Now, let's carry out these steps:

Step 1: Start with the initial number 34.

Step 2: Remove 4 units by subtracting.

Step 3: Calculate $34 - 4$.

Performing the subtraction, we find:

Therefore, the number of units left is $30$.

According to the multiple-choice options provided, the correct choice is:

• Option 2: $30$

To solve this problem, we'll follow these steps:

• Step 1: Identify the total number of blocks, which is $27$.
• Step 2: Identify how many blocks to remove, which is $7$.
• Step 3: Subtract the number of blocks to be removed from the total number of blocks.

Now, let's perform the calculation:
Step 3: We calculate $27 - 7 = 20$.

Therefore, the number of blocks remaining after removing 7 blocks from 27 is $20$.

To solve this problem, we'll perform a simple arithmetic subtraction, as follows:

• Step 1: Identify the initial number of units, which is 48.
• Step 2: Identify the number of units to subtract, which is 8.
• Step 3: Perform the subtraction $48 - 8$.

Let's carry out the calculation:
Step 1: We start with a total of 48 units.
Step 2: We subtract 8 units from 48.
Step 3: Calculating the subtraction, we find:

$48 - 8 = 40$

This means there are 40 units left after removing 8 units from 48.

Therefore, the solution to the problem is $40$.

To solve the problem of removing the hundreds from 325, follow these steps:

• Step 1: Identify the hundreds digit in the number 325. The hundreds digit is 3.
• Step 2: Convert the hundreds digit into a full hundred by multiplying it by 100: $3 \times 100 = 300$.
• Step 3: Subtract this total from the original number: $325 - 300$.
• Step 4: Calculate the result of this subtraction: $325 - 300 = 25$.

Therefore, the resulting exercise is $325 - 300 = 25$, and the final numerical answer is 25.

Among the given choices, the correct choice is:

$325-300=25$

To solve this problem, we need to "remove the tens" from the total number of blocks, which is 447:

• Step 1: Identify the tens digit in 447. The number 447 consists of the hundreds digit as 4, the tens digit as 4, and the units digit as 7.
• Step 2: Determine the value of the tens digit. The tens digit 4 represents a total value of $4 \times 10 = 40$.
• Step 3: Subtract the tens value from the total. We subtract 40 from 447: $447 - 40 = 407$

Therefore, the result of removing the tens from 447 is $447 - 40 = 407$.

This exercise corresponds to choice id="2": $447-40=407$.

To find how many blocks remain after removing the ones digit from 559, we follow these steps:

• Step 1: Determine the ones digit in 559. The number is 559, so the ones digit is 9.
• Step 2: Subtract the ones digit from the total number of blocks. This means calculating $559 - 9$.
• Step 3: Perform the subtraction: $559 - 9 = 550$.

Therefore, when the ones digit is removed, 550 blocks remain.

The correct answer to the problem is $559 - 9 = 550$.

To solve this problem, we'll be removing the hundreds and ones digits from the total 545 blocks and writing the resulting subtraction exercise.

• Step 1: Identify hundreds and ones contributions.
  Hundreds digit is 5, so hundred contribution = $5 \times 100 = 500$.
  Ones digit is 5, so one contribution = $5 \times 1 = 5$.
• Step 2: Sum the contributions from hundreds and ones.
  Total contribution to remove = $500 + 5 = 505$.
• Step 3: Subtract the total contribution from the original total.
  Subtraction exercise = $545 - 505$.
• Step 4: Calculate the result of the subtraction.
  Final result = $40$.

Therefore, the solution to the problem is $545 - 505 = 40$.