Rectangle Area Comparison: Finding Difference Between (x+4)(x+3) and (x+5)(x+2)

Polynomial Area Expansion with Algebraic Expressions

Look at the rectangles in the diagram below.

Which has a larger area and by how much?

x+4x+4x+4x+5x+5x+5ABx+3x+2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Determine which area is larger
00:03 We'll use the formula for calculating the area of a rectangle (length times width)
00:08 We'll substitute appropriate values according to the given data and calculate the area
00:13 Open parentheses properly, multiply each factor by each factor
00:23 Combine the terms
00:30 This is the expression for rectangle 1's area, now let's move to the second one
00:34 Again we'll use the formula and multiply the sides
00:38 Open parentheses properly, multiply each factor by each factor
00:49 Combine the terms
00:55 Compare the terms of the expressions, and find which is larger
01:00 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the rectangles in the diagram below.

Which has a larger area and by how much?

x+4x+4x+4x+5x+5x+5ABx+3x+2

2

Step-by-step solution

Let's calculate the area of each rectangle step by step:

Step 1: Calculate the area of Rectangle A.
- Dimensions are (x+4)(x+4) and (x+3)(x+3).
- The area is calculated as (x+4)×(x+3) (x+4) \times (x+3) .

Expanding this expression using the distributive property, we get:
(x+4)(x+3)=xx+x3+4x+43(x+4)(x+3) = x \cdot x + x \cdot 3 + 4 \cdot x + 4 \cdot 3
x2+3x+4x+12\Rightarrow x^2 + 3x + 4x + 12
x2+7x+12\Rightarrow x^2 + 7x + 12

Step 2: Calculate the area of Rectangle B.
- Dimensions are (x+5)(x+5) and (x+2)(x+2).
- The area is calculated as (x+5)×(x+2) (x+5) \times (x+2) .

Using the distributive property to expand:
(x+5)(x+2)=xx+x2+5x+52(x+5)(x+2) = x \cdot x + x \cdot 2 + 5 \cdot x + 5 \cdot 2
x2+2x+5x+10\Rightarrow x^2 + 2x + 5x + 10
x2+7x+10\Rightarrow x^2 + 7x + 10

Step 3: Compare the areas of Rectangle A and B.
- Area of Rectangle A: x2+7x+12 x^2 + 7x + 12
- Area of Rectangle B: x2+7x+10 x^2 + 7x + 10

Subtract the area of Rectangle B from the area of Rectangle A:
(x2+7x+12)(x2+7x+10)=(x2+7x+12)x27x10 (x^2 + 7x + 12) - (x^2 + 7x + 10) = (x^2 + 7x + 12) - x^2 - 7x - 10
x2x2+7x7x+1210 \Rightarrow x^2 - x^2 + 7x - 7x + 12 - 10
2 \Rightarrow 2

Thus, the area of Rectangle A is larger by 2 2 area units.

The correct answer, therefore, is: The area of rectangle A is larger by 2 area units.

3

Final Answer

The area of rectangle A is larger by 2 area units.

Key Points to Remember

Essential concepts to master this topic
  • Formula: Rectangle area equals length times width using FOIL method
  • Technique: Expand (x+4)(x+3) = x² + 7x + 12 systematically
  • Check: Subtract final expressions: (x² + 7x + 12) - (x² + 7x + 10) = 2 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute all terms when expanding
    Don't just multiply x·x and 4·3 = x² + 12! This skips the middle terms and gives wrong areas. Always use FOIL: First, Outer, Inner, Last to get all four products like x·x + x·3 + 4·x + 4·3.

Practice Quiz

Test your knowledge with interactive questions

It is possible to use the distributive property to simplify the expression below?

What is its simplified form?

\( (ab)(c d) \)

\( \)

FAQ

Everything you need to know about this question

Why can't I just multiply the numbers and ignore x?

+

Because x represents a variable length! The rectangles' areas depend on x. You must expand the entire expression (x+4)(x+3) (x+4)(x+3) to get the complete area formula.

What's the easiest way to expand these expressions?

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Use FOIL method: First terms (x·x), Outer terms (x·3), Inner terms (4·x), Last terms (4·3). Then combine like terms!

How do I know which rectangle is bigger without knowing x?

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Compare the expanded forms! Rectangle A gives x2+7x+12 x^2 + 7x + 12 and Rectangle B gives x2+7x+10 x^2 + 7x + 10 . Since 12 > 10, Rectangle A is always 2 units larger.

Why does the x² and 7x cancel out when comparing?

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Because both rectangles have identical x² and 7x terms! When you subtract one area from the other, these identical parts cancel out, leaving only the constant difference of 12 - 10 = 2.

Can I use specific numbers for x to check my answer?

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Absolutely! Try x = 1: Rectangle A = 5×4 = 20, Rectangle B = 6×3 = 18. The difference is 20-18 = 2, which matches our algebraic result!

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