Solve (2a+b)(3b-?) = 6ab+5a+2b: Find the Missing Term

Let's solve this problem step by step.

Step 1: Apply the distributive property to the left-hand side.
The expression $(2a+b)(3b-?)$ expands to:

$(2a + b)(3b - ?) = 2a(3b - ?) + b(3b - ?)$

Step 2: Distribute each term:

• First $2a(3b)$ gives $6ab$.
• Then $2a(-?)$ gives $-2a\cdot?$.
• Next $b(3b)$ gives $3b^2$.
• Finally $b(-?)$ gives $-b\cdot?$.

In equation form:

$= 6ab + 3b^2 - 2a? - b?$

Now, compare this with the given equation: $6ab + 5a + 2b$.

Notice that $3b^2$ doesn't present on the right-hand side, indicating no term in $b^2$ should exist. Moreover, right-hand terms $5a$ and $2b$ have no zero counterparts on complex variables (polynomial formation), indicating inconsistencies in all forms with possible simple polynomial inequivalence.

Step 3: Analysis shows inability to correlate purely intuitively with missing match coefficients specifically implies an inadequacy here in probabilistic assumptions, leading us to:

Therefore, the solution to the problem with the provided options is No adequate solution.