Rectangle Area Problem: Finding EBFD When EB = 1/5 AB and Area = 50

The area of a rectangle is 50.

$EB=\frac{1}{5}AB$

$EF\Vert BD$

Work out the area of the rectangle EBFD.

Since AB is 5 times larger than EB, the area of rectangle EBDF will be smaller than the area of rectangle ABCD accordingly

In other words, the ratio between the smaller rectangle to the larger one is $\frac{1}{5}$

$S_{\text{ABCD}}=5\times S_{EBFD}$

Let's input the known data into the formula:

$50=5\times S_{\text{EBFD}}$

$S_{\text{EBFD}}=10$