Rectangle Perimeter Problem: Finding the Distance Around a 21-Square-Unit Shape

Rectangle Perimeter with Given Area Dimensions

If the area of the rectangle is 21.

Determine the perimeter of the rectangle.

212121777333AAABBBDDDCCC

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1

Understand the problem

If the area of the rectangle is 21.

Determine the perimeter of the rectangle.

212121777333AAABBBDDDCCC

2

Step-by-step solution

Given that in a rectangle every pair of opposite sides are equal to each other, we can state that:

AB=CD=7 AB=CD=7

AC=BD=3 AC=BD=3

Now let's add all the sides together to calculate the perimeter:

3+7+3+7=6+14=20 3+7+3+7=6+14=20

3

Final Answer

20

Key Points to Remember

Essential concepts to master this topic
  • Rectangle Rule: Opposite sides are equal in length always
  • Technique: Add all four sides: 7 + 3 + 7 + 3
  • Check: Verify area equals length × width: 7 × 3 = 21 ✓

Common Mistakes

Avoid these frequent errors
  • Only adding two sides instead of all four
    Don't calculate 7 + 3 = 10 and call it the perimeter! This only gives you two adjacent sides, not the distance around. Perimeter means the total distance around all four sides. Always add all sides: 7 + 3 + 7 + 3 = 20.

Practice Quiz

Test your knowledge with interactive questions

Look at the rectangle below.

Side AB is 2 cm long and side BC has a length of 7 cm.

What is the perimeter of the rectangle?
222777AAABBBCCCDDD

FAQ

Everything you need to know about this question

Why do I need to add all four sides when opposite sides are equal?

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Even though opposite sides are equal, perimeter means the total distance around the entire rectangle. You're walking around the whole shape, so you count every side: length + width + length + width.

Can I use the formula P = 2(l + w) instead?

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Absolutely! P=2(l+w)=2(7+3)=2(10)=20 P = 2(l + w) = 2(7 + 3) = 2(10) = 20 . This formula is just a shortcut for adding all four sides, since you have two lengths and two widths.

How do I know which number is length and which is width?

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It doesn't matter! In this problem, you can call 7 the length and 3 the width, or vice versa. The perimeter will be the same either way: 20 units.

What if I'm given different dimensions but the same area?

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Different rectangles can have the same area but different perimeters. For example, a 1×21 rectangle also has area 21, but its perimeter is 2(1+21)=44 2(1 + 21) = 44 !

How can I check if my area calculation is right?

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Multiply length × width: 7×3=21 7 \times 3 = 21 . This should match the given area. If it doesn't, double-check that you're reading the dimensions correctly from the diagram.

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