Simplify √25 · ∛(√25): Multiple Radical Expression Problem

Radical Expressions with Nested Roots

Complete the following exercise:

25253= \sqrt{25}\cdot\sqrt[3]{\sqrt{25}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's solve this problem together.
00:16 Remember, the regular root is usually order two.
00:21 For a root of order C, with root B, we multiply the orders.
00:26 The result is the root of their product.
00:31 Now, let's use this formula in our exercise.
00:38 First, let's simplify twenty-five to five squared.
00:46 When there's a root of order C on A to the power of B,
00:52 it equals A to the power of B divided by C.
00:56 Let's apply this formula now.
00:59 Up next, we calculate the exponent parts.
01:09 When multiplying powers with the same base,
01:13 the result is the base with an exponent that's a sum of the pow ers.
01:18 Let's apply this to our exercise.
01:22 And there you have it. That's the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

25253= \sqrt{25}\cdot\sqrt[3]{\sqrt{25}}=

2

Step-by-step solution

To solve the problem 25253\sqrt{25} \cdot \sqrt[3]{\sqrt{25}}, follow these steps:

  • First, express each root in terms of exponents:
    • 25=251/2\sqrt{25} = 25^{1/2}
    • 253=251/23\sqrt[3]{\sqrt{25}} = \sqrt[3]{25^{1/2}}
  • Using the law of exponents (am)n=amn(a^m)^n = a^{m \cdot n}, simplify 251/23\sqrt[3]{25^{1/2}} as follows:
    • (251/2)1/3=25(1/2)(1/3)=251/6(25^{1/2})^{1/3} = 25^{(1/2) \cdot (1/3)} = 25^{1/6}
  • Now, multiply the two expressions:
    • 251/2251/6=25(1/2+1/6)25^{1/2} \cdot 25^{1/6} = 25^{(1/2 + 1/6)}
    • Calculate the sum of the exponents: 12+16=36+16=46=23\frac{1}{2} + \frac{1}{6} = \frac{3}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}
    • This gives: 252/325^{2/3}
  • Recognize 25=5225 = 5^2, thus: (52)2/3=52(2/3)=54/3(5^2)^{2/3} = 5^{2 \cdot (2/3)} = 5^{4/3}
  • Convert mixed fraction: 54/3=51+1/3=51135^{4/3} = 5^{1 + 1/3} = 5^{1\frac{1}{3}}

Therefore, the product 25253\sqrt{25} \cdot \sqrt[3]{\sqrt{25}} equals 5113\mathbf{5^{1\frac{1}{3}}}.

3

Final Answer

5113 5^{1\frac{1}{3}}

Key Points to Remember

Essential concepts to master this topic
  • Conversion: Express all radicals as fractional exponents first
  • Technique: Apply (am)n=amn (a^m)^n = a^{m \cdot n} to simplify 253 \sqrt[3]{\sqrt{25}}
  • Check: Verify 54/3=5113 5^{4/3} = 5^{1\frac{1}{3}} by calculating 54/3=543=6253 5^{4/3} = \sqrt[3]{5^4} = \sqrt[3]{625}

Common Mistakes

Avoid these frequent errors
  • Calculating nested radicals from the outside in
    Don't evaluate 25=5 \sqrt{25} = 5 first then try to multiply by 53 \sqrt[3]{5} = wrong approach! This makes the problem much harder and leads to incorrect simplification. Always convert all radicals to fractional exponents first, then use exponent laws to combine them systematically.

Practice Quiz

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FAQ

Everything you need to know about this question

Why do I need to convert radicals to fractional exponents?

+

Fractional exponents make it much easier to apply exponent laws! 25=251/2 \sqrt{25} = 25^{1/2} and 253=251/6 \sqrt[3]{\sqrt{25}} = 25^{1/6} can be multiplied using addition of exponents.

How do I handle the nested radical 253 \sqrt[3]{\sqrt{25}} ?

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Work from the inside out: First convert 25=251/2 \sqrt{25} = 25^{1/2} , then apply the cube root: 251/23=(251/2)1/3=251/6 \sqrt[3]{25^{1/2}} = (25^{1/2})^{1/3} = 25^{1/6} .

Why does 252/3=54/3 25^{2/3} = 5^{4/3} ?

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Since 25=52 25 = 5^2 , we can substitute: 252/3=(52)2/3=522/3=54/3 25^{2/3} = (5^2)^{2/3} = 5^{2 \cdot 2/3} = 5^{4/3} . This uses the power rule (am)n=amn (a^m)^n = a^{mn} .

How do I convert 54/3 5^{4/3} to mixed number form?

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Divide the exponent: 4÷3=1 4 ÷ 3 = 1 remainder 1 1 , so 54/3=51+1/3=5113 5^{4/3} = 5^{1 + 1/3} = 5^{1\frac{1}{3}} . The mixed number form is often preferred in final answers.

Can I solve this without using exponent laws?

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It's much more difficult! You'd need to calculate 253=53 \sqrt[3]{\sqrt{25}} = \sqrt[3]{5} and then find 5×53 5 \times \sqrt[3]{5} . Using exponent laws gives a cleaner, more systematic approach.

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