Multiply and Simplify: Fifth Root and Sixth Root of √3

Radical Expressions with Nested Roots

Complete the following exercise:

3536= \sqrt[5]{\sqrt{3}}\cdot\sqrt[6]{\sqrt{3}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:05 A "regular" root is of the order 2
00:13 When there is a root of the order (C) for root (B)
00:17 The result equals the root of the multiplication of the orders
00:21 Apply this formula to our exercise
00:31 Let's calculate the multiplication of orders
00:37 When we have a root of order (C) on number (A) to the power of (B)
00:40 The result equals number (A) to the power of (B divided by C)
00:44 Apply this formula to our exercise, where each number is to the power of 1
00:56 When we have multiplication between powers with equal bases
00:59 The result equals the base with power equal to the sum of the powers
01:04 Apply this formula to our exercise
01:07 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

3536= \sqrt[5]{\sqrt{3}}\cdot\sqrt[6]{\sqrt{3}}=

2

Step-by-step solution

To simplify the expression 3536 \sqrt[5]{\sqrt{3}} \cdot \sqrt[6]{\sqrt{3}} , follow these steps:

  • Step 1: Represent 3\sqrt{3} as 31/23^{1/2} because 3=31/2\sqrt{3} = 3^{1/2}.
  • Step 2: Express 35\sqrt[5]{\sqrt{3}} in exponential form: 35=(3)1/5=(31/2)1/5=3(1/2)×(1/5)=31/10\sqrt[5]{\sqrt{3}} = (\sqrt{3})^{1/5} = (3^{1/2})^{1/5} = 3^{(1/2) \times (1/5)} = 3^{1/10}.
  • Step 3: Express 36\sqrt[6]{\sqrt{3}} in exponential form: 36=(3)1/6=(31/2)1/6=3(1/2)×(1/6)=31/12\sqrt[6]{\sqrt{3}} = (\sqrt{3})^{1/6} = (3^{1/2})^{1/6} = 3^{(1/2) \times (1/6)} = 3^{1/12}.
  • Step 4: Multiply the two expressions using properties of exponents: 31/1031/12=3(1/10+1/12)3^{1/10} \cdot 3^{1/12} = 3^{(1/10 + 1/12)}.

Therefore, the simplified expression is 3110+112 3^{\frac{1}{10}+\frac{1}{12}} .

3

Final Answer

3110+112 3^{\frac{1}{10}+\frac{1}{12}}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Convert nested radicals to exponential form using am/n a^{m/n}
  • Technique: 35=(31/2)1/5=31/10 \sqrt[5]{\sqrt{3}} = (3^{1/2})^{1/5} = 3^{1/10}
  • Check: Same base allows adding exponents: 31/1031/12=3(1/10+1/12) 3^{1/10} \cdot 3^{1/12} = 3^{(1/10 + 1/12)}

Common Mistakes

Avoid these frequent errors
  • Multiplying the radical indices instead of adding exponents
    Don't multiply 5 × 6 = 30 to get 330 \sqrt[30]{3} ! This treats the problem like nested radicals are being combined incorrectly. Always convert to exponential form first, then add the exponents when multiplying powers with the same base.

Practice Quiz

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FAQ

Everything you need to know about this question

Why do I need to convert radicals to exponential form?

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Converting makes it easier to use exponent rules! an=a1/n \sqrt[n]{a} = a^{1/n} lets you work with fractions instead of confusing nested radical symbols.

How do I handle the nested square root inside?

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Start from the inside out: 3=31/2 \sqrt{3} = 3^{1/2} first, then apply the outer radical. So 35=(31/2)1/5 \sqrt[5]{\sqrt{3}} = (3^{1/2})^{1/5} .

When do I add exponents versus multiply them?

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Add exponents when multiplying powers with the same base: aman=am+n a^m \cdot a^n = a^{m+n} . Multiply exponents when raising a power to a power: (am)n=amn (a^m)^n = a^{mn} .

Do I need to simplify the fraction in the exponent?

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The answer 3110+112 3^{\frac{1}{10}+\frac{1}{12}} is correct as shown. You could add the fractions to get 31160 3^{\frac{11}{60}} , but both forms are acceptable.

What if the bases were different numbers?

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If you had different bases like 2536 \sqrt[5]{\sqrt{2}} \cdot \sqrt[6]{\sqrt{3}} , you couldn't combine them easily. The same base (3 in this problem) is what allows us to add exponents.

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