Simplify (5×12×4×6) Raised to Power (a+3bx): Complex Base Exponents

Power Properties with Product Bases

Simplify:

(51246)a+3bx (5\cdot12\cdot4\cdot6)^{a+3bx}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:04 When there is a power on a product of terms, all terms are raised to that power
00:14 Let's use this formula in our exercise
00:18 Raise each factor to the power
00:34 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify:

(51246)a+3bx (5\cdot12\cdot4\cdot6)^{a+3bx}

2

Step-by-step solution

Use the power property for a power in parentheses where there is a multiplication of its terms:

(xy)n=xnyn (x\cdot y)^n=x^n\cdot y^n

We apply this law to the problem expression:

(51246)a+3bx=5a+3bx12a+3bx4a+3bx6a+3bx (5\cdot12\cdot4\cdot6)^{a+3bx}=5^{a+3bx}12^{a+3bx}4^{a+3bx}6^{a+3bx}

When we apply a power to parentheses where its terms are multiplied, we do it separately and keep the multiplication.

Therefore, the correct answer is option d.

3

Final Answer

5a+3bx12a+3bx4a+3bx6a+3bx 5^{a+3bx}12^{a+3bx}4^{a+3bx}6^{a+3bx}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: (ab)n=anbn (a \cdot b)^n = a^n \cdot b^n for product bases
  • Technique: Apply exponent to each factor: (51246)a+3bx=5a+3bx12a+3bx4a+3bx6a+3bx (5\cdot12\cdot4\cdot6)^{a+3bx} = 5^{a+3bx}12^{a+3bx}4^{a+3bx}6^{a+3bx}
  • Check: Count factors in base (4) equals factors with exponent (4) ✓

Common Mistakes

Avoid these frequent errors
  • Computing the product inside parentheses first
    Don't calculate 5×12×4×6 = 1440 then write 1440a+3bx 1440^{a+3bx} = wrong simplified form! This eliminates the individual factors and makes further factoring impossible. Always distribute the exponent to each factor separately using (ab)n=anbn (a\cdot b)^n = a^n \cdot b^n .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply 5×12×4×6 first to get 1440?

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While 1440 is mathematically correct, the question asks you to simplify using exponent rules. Computing the product loses the individual prime factors, making it harder to factor or simplify further in more complex problems.

Do I apply the exponent to every single number?

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Yes! When you have (abcd)n (a\cdot b\cdot c\cdot d)^n , the exponent n applies to each factor separately: anbncndn a^n \cdot b^n \cdot c^n \cdot d^n .

What if the exponent was just a number like 3?

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The same rule applies! (51246)3=531234363 (5\cdot12\cdot4\cdot6)^3 = 5^3 \cdot 12^3 \cdot 4^3 \cdot 6^3 . Whether the exponent is a number or an algebraic expression like a+3bx, you distribute it to each factor.

Can I break this down further by factoring the numbers?

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Absolutely! You could factor 12=223 12 = 2^2 \cdot 3 and 4=22 4 = 2^2 and 6=23 6 = 2 \cdot 3 for even more simplification, but the question only asks for the basic power rule application.

Why is this form considered 'simplified'?

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This form shows the structure of the expression clearly. Each base factor keeps its exponent, making it easier to see patterns, combine like terms, or apply additional algebraic operations later.

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