Solve (2×4×8)^(a+3): Understanding Compound Power Expressions

Power Distribution with Multiple Base Factors

(248)a+3= (2\cdot4\cdot8)^{a+3}=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's solve this problem together.
00:13 When you have a power on a product, raise each term to that power.
00:22 We'll use this rule in our exercise.
00:27 Raise each factor to the power, one step at a time.
00:32 And that's how you find the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(248)a+3= (2\cdot4\cdot8)^{a+3}=

2

Step-by-step solution

Let's begin by using the distributing exponents rule (An exponent outside of a parentheses needs to be distributed across all the numbers and variables within the parentheses)

(xy)n=xnyn (x\cdot y)^n=x^n\cdot y^n We first apply this rule to the given problem:

(248)a+3=2a+34a+38a+3 (2\cdot4\cdot8)^{a+3}= 2^{a+3}4^{a+3}8^{a+3} When then we apply the power to each of the terms of the product inside the parentheses separately and maintain the multiplication.

The correct answer is option d.

3

Final Answer

2a+34a+38a+3 2^{a+3}4^{a+3}8^{a+3}

Key Points to Remember

Essential concepts to master this topic
  • Distribution Rule: Exponent applies to each factor in the product separately
  • Technique: (248)a+3=2a+34a+38a+3 (2\cdot4\cdot8)^{a+3} = 2^{a+3}\cdot4^{a+3}\cdot8^{a+3}
  • Check: Each base factor must have the same exponent (a+3) ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to the product result instead of individual factors
    Don't calculate (2×4×8) = 64 first, then write 64^(a+3)! This completely changes the algebraic structure and makes further simplification impossible. Always distribute the exponent to each individual factor: 2^(a+3) × 4^(a+3) × 8^(a+3).

Practice Quiz

Test your knowledge with interactive questions

\( (2^3)^6 = \)

FAQ

Everything you need to know about this question

Why can't I just multiply 2×4×8 = 64 first?

+

While 2×4×8=64 2\times4\times8 = 64 is correct, writing 64a+3 64^{a+3} loses the factor structure needed for algebraic manipulation. You need to keep the individual bases separate for further operations.

What's the difference between the correct answer and option A?

+

Option A shows 2a438a+3 2^a4^38^{a+3} with different exponents on each base. The correct answer has 2a+34a+38a+3 2^{a+3}4^{a+3}8^{a+3} - the same exponent (a+3) on all three bases.

Does the order of the factors matter?

+

No! Multiplication is commutative, so 2a+34a+38a+3 2^{a+3}\cdot4^{a+3}\cdot8^{a+3} equals 4a+32a+38a+3 4^{a+3}\cdot2^{a+3}\cdot8^{a+3} or any other arrangement of these factors.

Can I simplify this expression further?

+

Yes! Since 4=22 4 = 2^2 and 8=23 8 = 2^3 , you could rewrite everything in terms of base 2: 2a+3(22)a+3(23)a+3=26a+18 2^{a+3}\cdot(2^2)^{a+3}\cdot(2^3)^{a+3} = 2^{6a+18}

What if the exponent was just a number, like 3?

+

The same rule applies! (248)3=234383=864512 (2\cdot4\cdot8)^3 = 2^3\cdot4^3\cdot8^3 = 8\cdot64\cdot512 . You can then calculate the final numerical answer if needed.

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Exponents Rules questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations