Simplify a(b+c): Using the Distributive Property in Algebra

Distributive Property with Algebraic Terms

It is possible to use the distributive property to simplify the expression

a(b+c) a(b+c)

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Step-by-step video solution

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00:00 Simply
00:04 Open parentheses properly, multiply by each factor
00:10 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

It is possible to use the distributive property to simplify the expression

a(b+c) a(b+c)

2

Step-by-step solution

To solve the problem and apply the distributive property correctly, follow these steps:

  • Identify the expression, which is a(b+c) a(b+c) .
  • Apply the distributive property: multiply a a by each term inside the parentheses.

Applying this, we get:

  • a×b=ab a \times b = ab
  • a×c=ac a \times c = ac

Combine these two products:

The simplified expression is: ab+ac ab + ac .

This matches with answer choice 2: Yes, the answer ab+ac ab+ac .

3

Final Answer

Yes, the answer ab+ac ab+ac

Key Points to Remember

Essential concepts to master this topic
  • Rule: Multiply the outside term by each term inside parentheses
  • Technique: For a(b+c) a(b+c) , multiply: a×b=ab a \times b = ab and a×c=ac a \times c = ac
  • Check: Factor your answer back: ab+ac=a(b+c) ab + ac = a(b+c) matches original ✓

Common Mistakes

Avoid these frequent errors
  • Only multiplying the first term inside parentheses
    Don't multiply just a×b=ab a \times b = ab and forget about c c = wrong answer ab+c ab + c ! This violates the distributive property because every term inside parentheses must be multiplied. Always multiply the outside term by each and every term inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

Why can't I just ignore the parentheses and write abc?

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Because parentheses show addition, not multiplication! a(b+c) a(b+c) means "a times the sum of b and c", which is different from "a times b times c".

What if there are more than two terms in parentheses?

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The same rule applies! For a(b+c+d) a(b+c+d) , you get ab+ac+ad ab + ac + ad . Every term inside gets multiplied by the outside term.

Can I use the distributive property backwards?

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Yes! This is called factoring. If you see ab+ac ab + ac , you can factor out the common a a to get a(b+c) a(b+c) .

What if the term outside is negative?

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The distributive property still works! For a(b+c) -a(b+c) , you get abac -ab - ac . Remember: negative times positive equals negative.

How do I know if I applied it correctly?

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Try factoring your answer back to the original form. If ab+ac ab + ac factors back to a(b+c) a(b+c) , you did it right!

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