Simplify (x+c)(4+c): Distributive Property Practice

Distributive Property with Two Binomials

It is possible to use the distributive property to simplify the expression?

If so, what is its simplest form?

(x+c)(4+c)=? (x+c)(4+c) =\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:04 We'll properly open parentheses, multiply each factor by each factor
00:21 We'll calculate the multiplications
00:38 We'll arrange the expression
00:45 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

It is possible to use the distributive property to simplify the expression?

If so, what is its simplest form?

(x+c)(4+c)=? (x+c)(4+c) =\text{?}

2

Step-by-step solution

We simplify the given expression by opening the parentheses using the extended distributive property:

(x+y)(t+d)=xt+xd+yt+yd (\textcolor{red}{x}+\textcolor{blue}{y})(t+d)=\textcolor{red}{x}t+\textcolor{red}{x}d+\textcolor{blue}{y}t+\textcolor{blue}{y}d Keep in mind that in the distributive property formula mentioned above, we assume that the operation between the terms inside the parentheses is an addition operation, therefore, of course, we will not forget that the sign of the term's coefficient is ery important.

We will also apply the rules of multiplication of signs, so we can present any expression within parentheses that's opened with the distributive property as an expression with addition between all the terms.

In this expression we only have addition signs in parentheses, therefore we go directly to opening the parentheses,

We start by opening the parentheses:

(x+c)(4+c)x4+xc+c4+cc4x+xc+4c+c2 (\textcolor{red}{x}+\textcolor{blue}{c})(4+c)\\ \textcolor{red}{x}\cdot 4+\textcolor{red}{x}\cdot c+\textcolor{blue}{c}\cdot 4+\textcolor{blue}{c} \cdot c\\ 4x+xc+4c+c^2 To simplify this expression, we use the power law for multiplication between terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}

In the next step like terms come into play.

We define like terms as terms in which the variables (in this case, x and c) have identical powers (in the absence of one of the variables from the expression, we will refer to its power as zero power, this is because raising any number to the power of zero results in 1).

We will also use the substitution property, and we will order the expression from the highest to the lowest power from left to right (we will refer to the regular integer as the power of zero),

Keep in mind that in this new expression there are four different terms, this is because there is not even one pair of terms in which the variables (different) have the same power. Also it is already ordered by power, therefore the expression we have is the final and most simplified expression:4x+xc+4c+c2c2+xc+4x+4c \textcolor{purple}{4x}\textcolor{green}{+xc}\textcolor{black}{+4c}\textcolor{orange}{+c^2 }\\ \textcolor{orange}{c^2 }\textcolor{green}{+xc}\textcolor{purple}{+4x}\textcolor{black}{+4c}\\ We highlight the different terms using colors and, as emphasized before, we make sure that the main sign of the term is correct.

We use the substitution property for multiplication to note that the correct answer is option A.

3

Final Answer

Yes, the meaning is 4x+cx+4c+c2 4x+cx+4c+c^2

Key Points to Remember

Essential concepts to master this topic
  • FOIL Method: First, Outer, Inner, Last terms must all be multiplied
  • Technique: (x+c)(4+c) = x·4 + x·c + c·4 + c·c
  • Check: Count four terms in final answer: 4x + cx + 4c + c² ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to multiply all four combinations
    Don't just multiply x·4 and c·c = missing terms! This gives incomplete expansion like 4x + c². Always multiply each term in the first binomial by each term in the second binomial to get all four products.

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

Why do I get four terms when multiplying two binomials?

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Each term in the first parentheses must multiply with every term in the second parentheses. Since (x+c) has 2 terms and (4+c) has 2 terms, you get 2×2 = 4 different products!

Can I combine any of these terms: 4x + cx + 4c + c²?

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No! These are all unlike terms because they have different variable combinations. 4x has only x, cx has both x and c, 4c has only c, and c² has c squared.

What's the difference between cx and xc?

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There's no difference! Due to the commutative property of multiplication, cx = xc. You can write it either way in your final answer.

Do I always get exactly 4 terms when using FOIL?

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Initially yes, but sometimes you can combine like terms. For example, (x+2)(x+3) gives x² + 3x + 2x + 6, which simplifies to x² + 5x + 6 because 3x and 2x are like terms.

How can I remember to multiply all combinations?

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  • First terms: x × 4
  • Outer terms: x × c
  • Inner terms: c × 4
  • Last terms: c × c

FOIL helps you systematically get all four products!

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