Simplify Powers of 2: Solving 2³ × 2⁴ ÷ 2⁵

In order to simplify the given expression, we will use the following two laws of exponents:

a. Law of exponents for multiplication of terms with identical bases:

$a^m\cdot a^n=a^{m+n}$

b. Law of exponents for division of terms with identical bases:

$\frac{a^m}{a^n}=a^{m-n}$

Let's solve the given expression:

$\frac{2^3\cdot2^4}{2^5}=$First, since in the numerator we have multiplication of terms with identical bases, we'll use the law of exponents mentioned in a:

$\frac{2^3\cdot2^4}{2^5}= \\ \frac{2^{3+4}}{2^5}=\\ \frac{2^{7}}{2^5}=\\$We'll continue, since we have division of terms with identical bases, we'll use the law of exponents mentioned in b:

$\frac{2^{7}}{2^5}=\\ 2^{7-5}=\\ 2^2=\\ \boxed{4}$

Let's summarize the simplification of the given expression:

$\frac{2^3\cdot2^4}{2^5}= \\ \frac{2^{7}}{2^5}=\\ 2^2=\\ \boxed{4}$

Therefore, the correct answer is answer d.