Simplify the Nested Expression: (a^4)^6 Using Power Rules

Power of a Power with Exponent Multiplication

(a4)6= (a^4)^6=

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1

Understand the problem

(a4)6= (a^4)^6=

2

Step-by-step solution

We use the formula

(am)n=am×n (a^m)^n=a^{m\times n}

Therefore, we obtain:

a4×6=a24 a^{4\times6}=a^{24}

3

Final Answer

a24 a^{24}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a power to a power, multiply the exponents
  • Technique: (a4)6=a4×6=a24 (a^4)^6 = a^{4 \times 6} = a^{24}
  • Check: Count total multiplications: a4×a4×a4×a4×a4×a4=a24 a^4 \times a^4 \times a^4 \times a^4 \times a^4 \times a^4 = a^{24}

Common Mistakes

Avoid these frequent errors
  • Adding exponents instead of multiplying them
    Don't add 4 + 6 = 10 to get a10 a^{10} ! This confuses the power rule with addition rules and gives completely wrong results. Always multiply the exponents: (am)n=am×n (a^m)^n = a^{m \times n} .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why do I multiply the exponents instead of adding them?

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Because you're repeating the multiplication! (a4)6 (a^4)^6 means a4×a4×a4×a4×a4×a4 a^4 \times a^4 \times a^4 \times a^4 \times a^4 \times a^4 - that's 6 groups of 4, which equals 24 total factors of a.

What's the difference between a4×a6 a^4 \times a^6 and (a4)6 (a^4)^6 ?

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Great question! a4×a6=a4+6=a10 a^4 \times a^6 = a^{4+6} = a^{10} (you add when multiplying same bases). But (a4)6=a4×6=a24 (a^4)^6 = a^{4 \times 6} = a^{24} (you multiply when raising a power to a power).

How can I remember when to add vs multiply exponents?

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Look for parentheses! If you see (am)n (a^m)^n with parentheses, multiply the exponents. If you see am×an a^m \times a^n without parentheses around the first power, add the exponents.

Can I work this out step by step to check my answer?

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Absolutely! (a4)6 (a^4)^6 means a4×a4×a4×a4×a4×a4 a^4 \times a^4 \times a^4 \times a^4 \times a^4 \times a^4 . Using the rule am×an=am+n a^m \times a^n = a^{m+n} , you get a4+4+4+4+4+4=a24 a^{4+4+4+4+4+4} = a^{24} .

What if the base had a coefficient, like (2a4)6 (2a^4)^6 ?

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Apply the power to everything inside! (2a4)6=26×(a4)6=64a24 (2a^4)^6 = 2^6 \times (a^4)^6 = 64a^{24} . The coefficient gets raised to the 6th power too.

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