Simplify the Square Root Expression: √(5x⁴)

Radical Simplification with Perfect Square Variables

Solve the following exercise:

5x4= \sqrt{5x^4}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's simplify this expression together.
00:09 The square root of A, times the square root of B, means we find the root of A times B.
00:15 Use this idea. Change from root one to two.
00:20 Break down X to the power of four. That's X squared, then squared again.
00:26 When you square and then take the square root, the square disappears.
00:35 Apply this method to our problem.
00:38 And there you go. That's our solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

5x4= \sqrt{5x^4}=

2

Step-by-step solution

In order to simplify the given expression, apply the following three laws of exponents:

a. Definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. Law of exponents for an exponent applied to terms in parentheses:

(ab)n=anbn (a\cdot b)^n=a^n\cdot b^n

c. Law of exponents for an exponent raised to an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's start with converting the fourth root to an exponent using the law of exponents mentioned in a:

5x4=(5x4)12= \sqrt{5x^4}= \\ \downarrow\\ (5x^4)^{\frac{1}{2}}=

Next, use the law of exponents mentioned in b and apply the exponent to each factor inside of the parentheses:

(5x4)12=512(x4)12 (5x^4)^{\frac{1}{2}}= \\ 5^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}}

Let's continue, using the law of exponents mentioned in c and perform the exponent operation on the term with an exponent in the parentheses (the second term in the multiplication):

512(x4)12=512x412=512x2=5x2 5^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}} = \\ 5^{\frac{1}{2}}\cdot x^{4\cdot\frac{1}{2}}=\\ 5^{\frac{1}{2}}\cdot x^{2}=\\ \boxed{\sqrt{5}x^2}

In the final step, we converted the one-half power applied to the first term in the multiplication back to the fourth root form, again, according to the definition of root as an exponent mentioned in a (in the reverse direction).

Therefore, the correct answer is answer c.

3

Final Answer

5x2 \sqrt{5}x^2

Key Points to Remember

Essential concepts to master this topic
  • Exponent Law: Convert square root to exponent form using a=a12 \sqrt{a} = a^{\frac{1}{2}}
  • Technique: Apply (ab)n=anbn (ab)^n = a^n \cdot b^n to separate factors: (5x4)12=512x412 (5x^4)^{\frac{1}{2}} = 5^{\frac{1}{2}} \cdot x^{4 \cdot \frac{1}{2}}
  • Check: Square your answer: (5x2)2=5x4 (\sqrt{5}x^2)^2 = 5x^4 matches original expression ✓

Common Mistakes

Avoid these frequent errors
  • Taking the square root of the coefficient without separating it
    Don't simplify 5x4 \sqrt{5x^4} to 5x2 5x^2 by treating 5 like a perfect square! This ignores the square root of 5, which cannot be simplified to a whole number. Always keep 5 \sqrt{5} as 5 \sqrt{5} when 5 is not a perfect square.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why can't I just take the square root of each part separately?

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You can take the square root of each factor separately! That's exactly what we do: 5x4=5x4 \sqrt{5x^4} = \sqrt{5} \cdot \sqrt{x^4} . The key is recognizing that 5 \sqrt{5} stays as 5 \sqrt{5} since 5 isn't a perfect square.

How do I know when to leave a square root in radical form?

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Leave it in radical form when the number under the square root is not a perfect square. Perfect squares are 1, 4, 9, 16, 25, 36... Since 5 is between 4 and 9, it's not perfect, so 5 \sqrt{5} cannot be simplified further.

Why does x⁴ become x² when I take the square root?

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Because x4=x4÷2=x2 \sqrt{x^4} = x^{4 \div 2} = x^2 ! When you take a square root, you're raising to the power of 12 \frac{1}{2} , so you multiply the exponents: 4×12=2 4 \times \frac{1}{2} = 2 .

Can I write the answer as 2x√5 instead?

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No, that would be incorrect! The coefficient is 5 \sqrt{5} , not 2. Remember: 52.24 \sqrt{5} \approx 2.24 , which is different from 2. Always keep 5 \sqrt{5} in front of the variable.

How can I check if my answer is right?

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Square your entire answer and see if you get the original expression! (5x2)2=(5)2(x2)2=5x4=5x4 (\sqrt{5}x^2)^2 = (\sqrt{5})^2 \cdot (x^2)^2 = 5 \cdot x^4 = 5x^4

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