Solve 2×(3³ + √144): Order of Operations Practice

$2\times(3^3+\sqrt{144})=$

To solve the expression $2\times(3^3+\sqrt{144})$, we need to follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).

• Step 1: Begin by solving the part inside the parentheses $(3^3+\sqrt{144})$.

• Exponents: Calculate $3^3$.

  $3^3$ means $3 \times 3 \times 3 = 27$.

• Roots: Calculate $\sqrt{144}$.

  $\sqrt{144} = 12$, since 12 is the number that when multiplied by itself gives 144.

• Add the results of the exponent and the root: $27 + 12 = 39$.

• Step 2: Multiply the sum by 2:

  $2 \times 39 = 78$.

Therefore, the final answer is $78$.