Solve: (√36)/(√2·√3) + (√25)/5 | Adding Fractions with Square Roots

Radical Simplification with Perfect Squares

Solve the following exercise:

3623+255= \frac{\sqrt{36}}{\sqrt{2}\cdot\sqrt{3}}+\frac{\sqrt{25}}{5}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 Breakdown 36 into factors of 6 and 6
00:09 When multiplying the square root of a number (A) by the square root of another number (B)
00:12 The result equals the square root of their product (A times B)
00:16 Apply this formula to our exercise
00:31 Breakdown 25 into factors of 5 squared
00:38 Simplify wherever possible
00:43 The square root of any number (A) squared cancels out the square
00:47 Apply this formula to our exercise and cancel out the square
00:53 Any number divided by itself always equals 1
00:56 That's the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

3623+255= \frac{\sqrt{36}}{\sqrt{2}\cdot\sqrt{3}}+\frac{\sqrt{25}}{5}=

2

Step-by-step solution

To solve this problem, let's simplify each term in the expression step-by-step:

  • Simplify the first term 3623 \frac{\sqrt{36}}{\sqrt{2}\cdot\sqrt{3}} :

    • 36=6 \sqrt{36} = 6 , as 36 is a perfect square.
    • Apply the property of square roots: 23=6 \sqrt{2} \cdot \sqrt{3} = \sqrt{6} .
    • Rewrite the expression: 66=66 \frac{6}{\sqrt{6}} = \frac{6}{\sqrt{6}} .
    • Using the square root quotient property: 66=626=6 \frac{6}{\sqrt{6}} = \sqrt{\frac{6^2}{6}} = \sqrt{6} .
  • Simplify the second term 255 \frac{\sqrt{25}}{5} :

    • 25=5 \sqrt{25} = 5 , as 25 is a perfect square.
    • The expression becomes 55=1 \frac{5}{5} = 1 .
  • Combine the simplified terms: 6+1 \sqrt{6} + 1

Therefore, the solution to the problem is 6+1 \sqrt{6} + 1 .

3

Final Answer

6+1 \sqrt{6}+1

Key Points to Remember

Essential concepts to master this topic
  • Perfect Squares: Simplify √36 = 6 and √25 = 5 first
  • Product Property: Combine √2 · √3 = √6 before dividing
  • Check: Verify 6/√6 = √6 and 5/5 = 1, so √6 + 1 ✓

Common Mistakes

Avoid these frequent errors
  • Not simplifying perfect squares first
    Don't leave √36 and √25 unsimplified = unnecessarily complicated fractions! This makes the problem much harder than needed. Always simplify perfect squares like √36 = 6 and √25 = 5 immediately.

Practice Quiz

Test your knowledge with interactive questions

Choose the largest value

FAQ

Everything you need to know about this question

Why can't I just add the square roots together first?

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You can only add square roots with the same radicand (number under the radical). Since we have different expressions like 366 \frac{\sqrt{36}}{\sqrt{6}} and 255 \frac{\sqrt{25}}{5} , simplify each term separately first.

How do I know when to use the quotient property of square roots?

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Use ab=a2b \frac{a}{\sqrt{b}} = \sqrt{\frac{a^2}{b}} when you have a number divided by a square root. For example, 66=366=6 \frac{6}{\sqrt{6}} = \sqrt{\frac{36}{6}} = \sqrt{6} .

What if I get a different form for the same answer?

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Mathematical expressions can look different but be equal! For instance, 1+6 1 + \sqrt{6} and 6+1 \sqrt{6} + 1 are the same due to the commutative property of addition.

Why do we multiply √2 and √3 together?

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The product property states that ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} . So 23=6 \sqrt{2} \cdot \sqrt{3} = \sqrt{6} , which simplifies our denominator.

Can I rationalize the denominator instead?

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Yes! Rationalizing 66 \frac{6}{\sqrt{6}} by multiplying top and bottom by 6 \sqrt{6} gives 666=6 \frac{6\sqrt{6}}{6} = \sqrt{6} , the same result!

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