Solve Nested Square Roots: √√2 × √√4 Product Evaluation

Radical Operations with Nested Square Roots

Complete the following exercise:

24= \sqrt{\sqrt{2}}\cdot\sqrt{\sqrt{4}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A 'regular' root raised to the second power
00:11 When there is a root of order (C) for root (B)
00:14 The result equals the root of the product of the orders
00:17 Apply this formula to our exercise
00:31 When we have a product of 2 numbers (A and B) in a root of order (C)
00:35 The result equals their product (A times B) in a root of order (C)
00:39 Apply this formula to our exercise
00:46 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

24= \sqrt{\sqrt{2}}\cdot\sqrt{\sqrt{4}}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify each term individually.
  • Step 2: Multiply the simplified terms together.
  • Step 3: Compare with choices if necessary.

Let's begin:

Step 1: Simplify each term:

The expression is 24 \sqrt{\sqrt{2}} \cdot \sqrt{\sqrt{4}} .

- Simplifying 2\sqrt{\sqrt{2}}: A root of a root involves multiplying the indices. We have 222\sqrt[2]{\sqrt[2]{2}}, which becomes 24\sqrt[4]{2}.

- Simplifying 4\sqrt{\sqrt{4}}: Note that 4=2\sqrt{4} = 2, so 2=2\sqrt{2} = \sqrt{2}.

Conclusively, 4=2\sqrt{\sqrt{4}} = \sqrt{2}.

Step 2: Multiply the simplified terms:

Now, multiply 24×2\sqrt[4]{2} \times \sqrt{2}:

242=2×21/24=23/24=84\sqrt[4]{2} \cdot \sqrt{2} = \sqrt[4]{2 \times 2^{1/2}} = \sqrt[4]{2^{3/2}} = \sqrt[4]{8}.

Therefore, our simplified expression is 84\sqrt[4]{8}.

Step 3: Compare with answer choices:

The correct choice is 84\sqrt[4]{8}, matching choice 3.

Therefore, the solution to the problem is 84 \sqrt[4]{8} .

3

Final Answer

84 \sqrt[4]{8}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Nested radicals combine by multiplying the indices
  • Technique: Convert 2 \sqrt{\sqrt{2}} to 24 \sqrt[4]{2} and simplify 4=2 \sqrt{\sqrt{4}} = \sqrt{2}
  • Check: Verify 84848484=8 \sqrt[4]{8} \cdot \sqrt[4]{8} \cdot \sqrt[4]{8} \cdot \sqrt[4]{8} = 8

Common Mistakes

Avoid these frequent errors
  • Adding radicands instead of using product rule
    Don't add 2 + 4 = 6 to get 64 \sqrt[4]{6} ! This ignores the nested structure and product rule. The radicands multiply under the radical, so 242=2224=84 \sqrt[4]{2} \cdot \sqrt{2} = \sqrt[4]{2 \cdot 2^2} = \sqrt[4]{8} . Always apply radical multiplication rules correctly.

Practice Quiz

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Choose the largest value

FAQ

Everything you need to know about this question

How do I handle a square root inside another square root?

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When you have nested radicals like a \sqrt{\sqrt{a}} , think of it as a22 \sqrt[2]{\sqrt[2]{a}} . The indices multiply: 2 × 2 = 4, so a=a4 \sqrt{\sqrt{a}} = \sqrt[4]{a} .

Why does 4 \sqrt{\sqrt{4}} equal 2 \sqrt{2} ?

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First simplify the inner radical: 4=2 \sqrt{4} = 2 . Then take the square root of that result: 2 \sqrt{2} . So 4=2 \sqrt{\sqrt{4}} = \sqrt{2} .

How do I multiply radicals with different indices?

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Convert to the same index first! 242 \sqrt[4]{2} \cdot \sqrt{2} becomes 24224=244=84 \sqrt[4]{2} \cdot \sqrt[4]{2^2} = \sqrt[4]{2 \cdot 4} = \sqrt[4]{8} . Always find a common index before multiplying.

Can I simplify 84 \sqrt[4]{8} further?

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Yes! Since 8=23 8 = 2^3 , we have 84=234=23/4 \sqrt[4]{8} = \sqrt[4]{2^3} = 2^{3/4} . But 84 \sqrt[4]{8} is the simplest radical form since 8 has no perfect fourth power factors.

What's the difference between 24 \sqrt[4]{2} and 84 \sqrt[4]{8} ?

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241.19 \sqrt[4]{2} \approx 1.19 while 841.68 \sqrt[4]{8} \approx 1.68 . The radicand (number under the radical) makes a big difference in the final value!

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