Solve (9·3)÷8^0: Zero Exponent Division Problem

Think of it as the pattern rule! When you divide powers: $8^3 \div 8^3 = 8^{3-3} = 8^0$. Since any number divided by itself equals 1, we get $8^0 = 1$!

$0^0$ is actually undefined in mathematics! The zero exponent rule only works for non-zero bases. So $8^0 = 1$, but $0^0$ is undefined.

First calculate: $9 \times 3 = 27$. Then recognize that $9 = 3^2$, so $3^2 \times 3^1 = 3^{2+1} = 3^3$. Finally check: $3^3 = 3 \times 3 \times 3 = 27$ ✓

There's no 8 in the numerator to cancel! We have $\frac{9 \times 3}{8^0}$, not $\frac{8 \times 3}{8^0}$. Only identical factors can be cancelled.

Not necessary for this problem! You can solve it step-by-step: $8^0 = 1$, then $9 \times 3 = 27$. Converting to $3^3$ is just the final step to match the answer choices.