Solve ((9xyz)^3)^4 + (a^y)^x: Complex Compound Exponents

Power Rules with Multiple Exponent Layers

Solve the following problem:

((9xyz)3)4+(ay)x= ? ((9xyz)^3)^4+(a^y)^x=\text{ ?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following expression
00:03 When there is a power of a power, the combined power is the product of the powers
00:13 Let's use this formula in our exercise
00:20 Multiply the exponents
00:31 When there is a power of a product, all terms are raised to that power
00:41 Let's use this formula in our exercise
00:46 Raise each factor to the power
00:52 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

((9xyz)3)4+(ay)x= ? ((9xyz)^3)^4+(a^y)^x=\text{ ?}

2

Step-by-step solution

We'll use the power rule for a power:

(bm)n=bmn (b^m)^n=b^{m\cdot n}

We'll apply this rule to the expression in the problem in two stages:

((9xyz)3)4+(ay)x=(9xyz)34+(ay)x=(9xyz)12+ayx ((9xyz)^3)^4+(a^y)^x= (9xyz)^{3\cdot4}+(a^y)^x=(9xyz)^{12}+a^{yx}

In the first stage, we apply the above rule initially to the first term in the expression and then proceed to deal with the outer parentheses. We then simplify the expression in the exponent whilst simultaneously applying the power rule to the second term in the sum in the problem's expression.

We'll continue by recalling the rule for powers that applies to parentheses containing the multiplication of terms:

(wt)n=wntn (w\cdot t)^n=w^n\cdot t^n

We'll apply this rule to the expression that we obtained in the last stage:

(9xyz)12+(ay)x=912x12y12z12+ayx (9xyz)^{12}+(a^y)^x =9^{12} x^{12} y^{12}z^{12}+a^{yx}

We apply the aforementioned power rule to the first term in the sum in the expression that we obtained in the last stage, and apply the power on the parentheses to each of the multiplication terms inside the parentheses.

Let's summarize the solution steps so far:

((9xyz)3)4+(ay)x=(9xyz)12+ayx=912x12y12z12+ayx ((9xyz)^3)^4+(a^y)^x=(9xyz)^{12}+a^{yx} =9^{12} x^{12} y^{12} z^{12}+a^{yx}

Therefore the correct answer is answer D.

3

Final Answer

912x12y12z12+ayx 9^{12}x^{12}y^{12}z^{12}+a^{yx}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a power to a power, multiply exponents
  • Technique: Apply (bm)n=bmn (b^m)^n = b^{m \cdot n} first, then distribute exponents
  • Check: Verify each base has correct exponent: 9 gets 12, variables get 12 ✓

Common Mistakes

Avoid these frequent errors
  • Adding exponents instead of multiplying them
    Don't add 3+4=7 to get (9xyz)7 (9xyz)^7 = wrong structure! Adding only works for same bases multiplied together. Always multiply exponents when raising a power to a power: ((9xyz)3)4=(9xyz)3×4=(9xyz)12 ((9xyz)^3)^4 = (9xyz)^{3 \times 4} = (9xyz)^{12} .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why do I multiply 3×4 instead of adding 3+4?

+

The power rule (bm)n=bmn (b^m)^n = b^{m \cdot n} requires multiplication because you're applying the inner exponent multiple times. Think of it as: ((9xyz)3)4 ((9xyz)^3)^4 means (9xyz)3 (9xyz)^3 multiplied by itself 4 times!

Do I apply the exponent 12 to each variable separately?

+

Yes! When you have (9xyz)12 (9xyz)^{12} , the exponent distributes to each factor: 912x12y12z12 9^{12} \cdot x^{12} \cdot y^{12} \cdot z^{12} . Each variable and number gets raised to the 12th power.

What about the second term (a^y)^x?

+

Apply the same power rule: (ay)x=ayx=ayx (a^y)^x = a^{y \cdot x} = a^{yx} . The order doesn't matter for multiplication, so yx and xy are the same.

Can I simplify this expression further?

+

No, this is as simplified as it gets! You have two completely different terms: 912x12y12z12 9^{12}x^{12}y^{12}z^{12} and ayx a^{yx} . Since they don't share common factors, you just add them with a + sign.

Why can't I combine the two terms in the final answer?

+

The terms 912x12y12z12 9^{12}x^{12}y^{12}z^{12} and ayx a^{yx} have different variables and structures. You can only combine like terms - terms with exactly the same variable parts and exponents.

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