Solve for Weight Distribution: Finding Orange Quantities in Two Boxes with 61½ kg Total

System of Equations with Mixed Numbers

Jose picked oranges. The total weight of the oranges Jose picked is 6112 61\frac{1}{2} kilograms.

In the red box there are 5kg of oranges more than in the blue box.

How many oranges are in each box?

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Step-by-step written solution

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1

Understand the problem

Jose picked oranges. The total weight of the oranges Jose picked is 6112 61\frac{1}{2} kilograms.

In the red box there are 5kg of oranges more than in the blue box.

How many oranges are in each box?

2

Step-by-step solution

To solve this problem, follow these steps:

  • Define the variables: Let xx be the weight of oranges in the blue box.

  • Set up the equation: Since the red box has 5 kg more than the blue box, its weight is x+5x + 5. The total weight of the two boxes is given as 611261 \frac{1}{2} kg. Thus, the equation is:

x+(x+5)=6112x + (x + 5) = 61 \frac{1}{2}

Now, simplify and solve the equation step by step:

  • Combine like terms: 2x+5=61122x + 5 = 61 \frac{1}{2}

  • Convert the mixed number to an improper fraction for easier calculations: 6112=123261 \frac{1}{2} = \frac{123}{2}

  • Write the equation with the fraction: 2x+5=12322x + 5 = \frac{123}{2}

  • Subtract 5 from both sides: 2x=123252x = \frac{123}{2} - 5

  • Convert 5 to a fraction with the same denominator: 5=1025 = \frac{10}{2}

  • Subtract the fractions: 2x=1232102=11322x = \frac{123}{2} - \frac{10}{2} = \frac{113}{2}

  • Divide both sides by 2 to solve for xx: x=1132÷2=1134x = \frac{113}{2} \div 2 = \frac{113}{4}

Thus, the weight of oranges in the blue box is x=1134=2814x = \frac{113}{4} = 28 \frac{1}{4} kg.

The red box's oranges weigh x+5=1134+204=1334=3314x + 5 = \frac{113}{4} + \frac{20}{4} = \frac{133}{4} = 33 \frac{1}{4} kg.

Therefore, the solution is:

blue box 2814 28\frac{1}{4} red box 3314 33\frac{1}{4}

3

Final Answer

blue box 2814 28\frac{1}{4} red box 3314 33\frac{1}{4}

Key Points to Remember

Essential concepts to master this topic
  • Variables: Let x = smaller quantity, set up equation with difference
  • Technique: Convert 6112 61\frac{1}{2} to 1232 \frac{123}{2} for easier calculation
  • Check: Verify 2814+3314=6112 28\frac{1}{4} + 33\frac{1}{4} = 61\frac{1}{2}

Common Mistakes

Avoid these frequent errors
  • Setting up the equation incorrectly with variables
    Don't use separate variables for both boxes like x and y = creates two unknowns! This makes the problem unnecessarily complex. Always define one variable for the smaller amount and express the larger as (x + difference).

Practice Quiz

Test your knowledge with interactive questions

Solve for X:

\( x - 3 + 5 = 8 - 2 \)

FAQ

Everything you need to know about this question

Why do I only use one variable instead of two?

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Using one variable is simpler! Since we know the red box has exactly 5 kg more, we can express it as x + 5 instead of creating a second variable.

How do I work with mixed numbers in equations?

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Convert mixed numbers to improper fractions first! For example, 6112=1232 61\frac{1}{2} = \frac{123}{2} . This makes addition and subtraction much easier.

What if I get confused about which box is which?

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Always let x represent the smaller amount (blue box). Then the larger amount is automatically x + 5 (red box). This keeps everything organized!

How do I convert my final fraction back to a mixed number?

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Divide the numerator by the denominator: 1134=2814 \frac{113}{4} = 28\frac{1}{4} because 113 ÷ 4 = 28 remainder 1.

Can I solve this without using fractions?

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You could work in decimals (61.5 61.5 kg), but fractions are more precise and avoid rounding errors. Mixed numbers give exact answers!

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