Solve for X: Rectangle AEFD with Perimeter 30 and Expression 2x+3

The rectangle below is composed of two smaller rectangles.

Calculate x given that the perimeter of rectangle AEFD is 30.

AAABBBCCCDDDEEEFFF4+2x2x+32-x

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Opposite sides are equal in rectangle ABCD, EBFC
00:20 Opposite sides are equal in rectangle AEDF
00:34 The perimeter of the rectangle equals the sum of its sides
00:43 Let's substitute appropriate values and solve for X
01:28 Collect like terms
01:50 Isolate X
02:07 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

The rectangle below is composed of two smaller rectangles.

Calculate x given that the perimeter of rectangle AEFD is 30.

AAABBBCCCDDDEEEFFF4+2x2x+32-x

2

Step-by-step solution

To solve the problem, we'll begin by setting up the equation for the perimeter of rectangle AEFD AEFD :

The perimeter P P of a rectangle is given by the formula:

P=2×(length+width) P = 2 \times (\text{length} + \text{width})

We're told that the perimeter of rectangle AEFD AEFD is 30. The length is 2x+3 2x + 3 and the width is 2x 2 - x . Thus, the perimeter equation is:

2×((2x+3)+(2x))=30 2 \times ((2x + 3) + (2 - x)) = 30

Let's simplify the expression inside the parentheses:

=2×((2x+3)+2x) = 2 \times ((2x + 3) + 2 - x) =2×(x+5) = 2 \times (x + 5)

So the equation becomes:

2×(x+5)=30 2 \times (x + 5) = 30

Now, distribute the 2:

2x+10=30 2x + 10 = 30

Subtract 10 from both sides of the equation:

2x=20 2x = 20

Divide both sides by 2 to solve for x x :

x=10÷2 x = 10 \div 2 x=2 x = 2

Therefore, the value of x x that satisfies the given perimeter is x=2 x = 2 .

3

Final Answer

2

Practice Quiz

Test your knowledge with interactive questions

Look at the rectangle ABCD below.

Side AB is 6 cm long and side BC is 4 cm long.

What is the area of the rectangle?
666444AAABBBCCCDDD

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