Solve Square Root Expression: √36 × √49 + 7² × 2

$\sqrt{36}\times\sqrt{49}+7^2\times2=$

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$\sqrt{36}\times\sqrt{49}+7^2\times2=$

The given expression is: $\sqrt{36}\times\sqrt{49}+7^2\times2$ .

First, calculate the square roots: $\sqrt{36} = 6$ and $\sqrt{49} = 7$ .

Multiply the square roots: $6 \times 7 = 42$ .

Next, calculate the square: $7^2 = 49$ .

Multiply the result by 2: $49 \times 2 = 98$ .

Finally, add the two results: $42+98=140$ .

Thus, the answer is: $140$ .

140

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