Solve: √9·3² + 2³·√4 | Mixed Operations Expression

Order of Operations with Radicals and Exponents

Solve:

932+234 \sqrt{9}\cdot3^2+2^3\cdot\sqrt{4}

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve:

932+234 \sqrt{9}\cdot3^2+2^3\cdot\sqrt{4}

2

Step-by-step solution

First, we need to evaluate the square roots: 9=3 \sqrt{9} = 3 and 4=2 \sqrt{4} = 2 .

Substitute these values back into the expression:

332+232 3\cdot3^2+2^3\cdot2

Calculate each term separately:

  • 32=9 3^2 = 9 , so 39=27 3\cdot9 = 27

  • 23=8 2^3 = 8 , so 82=16 8\cdot2 = 16

Add these values together:

27+16=43 27+16=43

3

Final Answer

43

Key Points to Remember

Essential concepts to master this topic
  • PEMDAS Rule: Evaluate radicals and exponents before multiplication and addition
  • Technique: Calculate 9=3 \sqrt{9} = 3 and 32=9 3^2 = 9 first
  • Check: Substitute values: 3·9 + 8·2 = 27 + 16 = 43 ✓

Common Mistakes

Avoid these frequent errors
  • Adding before completing multiplication
    Don't try to add 27 + 2³ = 35 then multiply by 2 = 70! This ignores order of operations and gives wrong answers. Always complete all multiplications first, then add the final results.

Practice Quiz

Test your knowledge with interactive questions

What is the result of the following equation?

\( 36-4\div2 \)

FAQ

Everything you need to know about this question

Do I solve radicals or exponents first?

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Both radicals and exponents have the same priority in PEMDAS! Work from left to right when they appear together. In this problem, 9 \sqrt{9} and 32 3^2 can be solved in either order.

Why can't I just work left to right through everything?

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Order of operations (PEMDAS) ensures everyone gets the same answer! Without it, 332 3 \cdot 3^2 could be interpreted as (33)2=81 (3 \cdot 3)^2 = 81 instead of the correct 39=27 3 \cdot 9 = 27 .

What if I get a different answer when checking?

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If your check doesn't work, go back and re-evaluate each step. Make sure you calculated 9=3 \sqrt{9} = 3 , 32=9 3^2 = 9 , 23=8 2^3 = 8 , and 4=2 \sqrt{4} = 2 correctly.

Can I use a calculator for the square roots?

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Absolutely! But try to recognize perfect squares like 9=3 \sqrt{9} = 3 and 4=2 \sqrt{4} = 2 without a calculator. It makes the problem much faster!

Why do we multiply before adding in PEMDAS?

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Multiplication represents repeated addition, so it's a 'stronger' operation. Think of 39+16 3 \cdot 9 + 16 as 'three groups of 9, plus 16 more' rather than mixing everything together.

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