Solve: Square Root of 16 Times 4 Squared Minus 3 Cubed

Solve:

1642331 \sqrt{16}\cdot4^2-3^3\cdot\sqrt{1}

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Step-by-step written solution

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1

Understand the problem

Solve:

1642331 \sqrt{16}\cdot4^2-3^3\cdot\sqrt{1}

2

Step-by-step solution

Begin by evaluating the square roots: 16=4 \sqrt{16} = 4 and 1=1 \sqrt{1} = 1 .

Substitute these back into the expression:

442331 4\cdot4^2-3^3\cdot1

Calculate each term:

  • 42=16 4^2 = 16 , so 416=64 4\cdot16 = 64

  • 33=27 3^3 = 27 , so 271=27 27\cdot1 = 27

Subtract the second result from the first:

6427=37 64 - 27 = 37

3

Final Answer

37

Practice Quiz

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What is the result of the following equation?

\( 36-4\div2 \)

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