Solve Square Root Expression: Simplifying √(4x^4)

Square Root Simplification with Variable Exponents

Solve the following exercise:

4x4= \sqrt{4x^4}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's simplify this expression.
00:09 The square root of A, times the square root of B
00:14 is equal to the square root of A times B.
00:18 We'll use this formula to solve our problem.
00:22 First, think of 4 as 2 squared.
00:28 And think of X to the fourth as X squared, squared.
00:33 Remember, the square root of a number squared is just the number.
00:38 Let's apply this to our exercise.
00:41 And there you have it! That's our solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

4x4= \sqrt{4x^4}=

2

Step-by-step solution

In order to simplify the given expression, apply the following three laws of exponents:

a. Definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. Law of exponents for an exponent applied to terms in parentheses:

(ab)n=anbn (a\cdot b)^n=a^n\cdot b^n

c. Law of exponents for an exponent raised to an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n}

Begin by converting the fourth root to an exponent using the law of exponents mentioned in a.:

4x4=(4x4)12= \sqrt{4x^4}= \\ \downarrow\\ (4x^4)^{\frac{1}{2}}=

Proceed whilst using the law of exponents mentioned in b. and apply the exponent to each factor in the parentheses:

(4x4)12=412(x4)12 (4x^4)^{\frac{1}{2}}= \\ 4^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}}

We'll continue, using the law of exponents mentioned in c. and perform the exponent applied to the term with an exponent in parentheses (the second factor in the multiplication):

412(x4)12=412x412=412x2=4x2=2x2 4^{\frac{1}{2}}\cdot(x^4)^{{\frac{1}{2}}} = \\ 4^{\frac{1}{2}}\cdot x^{4\cdot\frac{1}{2}}=\\ 4^{\frac{1}{2}}\cdot x^{2}=\\ \sqrt{4}\cdot x^2=\\ \boxed{2x^2}

In the final steps, we first converted the power of one-half applied to the first factor in the multiplication back to the fourth root form, again, according to the definition of root as an exponent mentioned in a. (in reverse) and then calculated the known fourth root of 4.

Therefore, the correct answer is answer b.

3

Final Answer

2x2 2x^2

Key Points to Remember

Essential concepts to master this topic
  • Root Definition: Convert square roots to fractional exponents: a=a12 \sqrt{a} = a^{\frac{1}{2}}
  • Power Distribution: Apply exponents to each factor: (4x4)12=412(x4)12 (4x^4)^{\frac{1}{2}} = 4^{\frac{1}{2}} \cdot (x^4)^{\frac{1}{2}}
  • Check: Verify by squaring result: (2x2)2=4x4 (2x^2)^2 = 4x^4 matches original expression ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to apply the square root to the exponent
    Don't just take the square root of the coefficient and ignore the variable's exponent = getting 2x instead of 2x²! This happens when you treat √(4x⁴) like √4 · x⁴. Always apply the ½ exponent to both the coefficient AND the variable: (4x⁴)^(½) = 4^(½) · (x⁴)^(½) = 2x².

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why does x⁴ become x² and not just x?

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When you take the square root of x4 x^4 , you're really applying the exponent rule: (x4)12=x412=x2 (x^4)^{\frac{1}{2}} = x^{4 \cdot \frac{1}{2}} = x^2 . Think of it this way: what number times itself gives you x4 x^4 ? It's x2 x^2 because x2x2=x4 x^2 \cdot x^2 = x^4 !

Can I just divide the exponent by 2?

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Yes! That's exactly right. Taking a square root is the same as multiplying the exponent by 12 \frac{1}{2} , which means dividing by 2. So x4=x4÷2=x2 \sqrt{x^4} = x^{4 \div 2} = x^2 .

What if the number under the square root isn't a perfect square?

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Great question! In this problem, 4 is a perfect square (4=2 \sqrt{4} = 2 ), so we get a clean answer. If it weren't, like 3x4 \sqrt{3x^4} , you'd get x23 x^2\sqrt{3} as your final answer.

How do I check if my answer is correct?

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Square your final answer and see if you get back to the original expression! For 2x2 2x^2 : (2x2)2=22(x2)2=4x4 (2x^2)^2 = 2^2 \cdot (x^2)^2 = 4x^4 . Perfect match!

Why do we need to use exponent laws instead of just calculating?

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Exponent laws give you a systematic method that works for any expression, not just simple ones. Plus, they help you avoid mistakes and understand why the math works, making you stronger at more complex problems!

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