Solve the following exercise:
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Solve the following exercise:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The denominators are , , and . The smallest number that is a multiple of all these denominators is , so our LCD is .
Step 2: Convert each fraction to have a denominator of :
Step 3: Subtract the fractions, now rewritten as having the same denominator:
.
Subtract the numerators:
The resulting fraction is .
We simplify by dividing both the numerator and the denominator by their greatest common divisor, which is :
.
Therefore, the simplified result of the operation is .
\( \frac{1}{3}+\frac{1}{4}= \)
Fractions represent parts of a whole, not separate numbers! You need the same-sized pieces (same denominator) before you can subtract. It's like trying to subtract 2 apples from 3 oranges - you need to convert to the same unit first.
List the multiples of each denominator until you find the smallest number that appears in all lists. For 6, 4, and 12: multiples of 12 (12, 24...) already include 6 and 4 as factors, so 12 is the LCD!
Yes, always simplify! Look for the greatest common factor of the numerator and denominator. For , both 4 and 12 are divisible by 4, giving us .
Great! That fraction stays the same. In this problem, already had denominator 12, so we only needed to convert the other fractions.
Check these common errors: Did you find the correct LCD? Did you multiply both numerator and denominator by the same number? Did you subtract all numerators correctly? Did you simplify the final fraction?
The systematic approach IS the shortcut! Find LCD → Convert → Subtract → Simplify. Trying to skip steps usually leads to mistakes and takes longer to fix.
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