Solve the Linear Equation: 2(x+4)+8=0 Step by Step

Linear Equations with Distributive Property

Determine the value of x x :

2(x+4)+8=0 2(x+4)+8=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solution
00:03 Open parentheses properly, multiply by each factor
00:13 Collect terms
00:22 Arrange the equation so that one side has only the unknown X
00:28 Isolate X
00:38 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Determine the value of x x :

2(x+4)+8=0 2(x+4)+8=0

2

Step-by-step solution

Let's first expand the parentheses using the formula:

a(x+b)=ax+ab a(x+b)=ax+ab

(2×x)+(2×4)+8=0 (2\times x)+(2\times4)+8=0

2x+8+8=0 2x+8+8=0

Next, we will substitute in our terms accordingly:

2x+16=0 2x+16=0

Then, we will move the 16 to the left-hand side, keeping the appropriate sign:

2x=16 2x=-16

Finally, we divide both sides by 2:

2x2=162 \frac{2x}{2}=-\frac{16}{2}

x=8 x=-8

3

Final Answer

x=8 x=-8

Key Points to Remember

Essential concepts to master this topic
  • Distribution Rule: Multiply each term inside parentheses by outside coefficient
  • Technique: 2(x+4)=2x+8 2(x+4) = 2x + 8 before combining like terms
  • Check: Substitute x=8 x = -8 : 2(8+4)+8=8+8=0 2(-8+4)+8 = -8+8 = 0

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute to all terms inside parentheses
    Don't multiply only the first term: 2(x+4) ≠ 2x+4 = wrong answer! This ignores the second term and gives x = -6 instead of x = -8. Always multiply the outside number by every term inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( 5x=0 \)

FAQ

Everything you need to know about this question

Why do I need to distribute first instead of just moving terms around?

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The parentheses create a group that must be expanded first. You can't move individual terms inside parentheses until you've distributed the coefficient to each term.

What's the difference between 2(x+4) and 2x+4?

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2(x+4)=2x+8 2(x+4) = 2x + 8 because you multiply both x and 4 by 2. But 2x+4 2x + 4 means only the x is multiplied by 2. Big difference!

Can I solve this equation without distributing?

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Not easily! You could divide both sides by 2 first, but that creates fractions. Distributing first keeps everything as whole numbers and makes the algebra cleaner.

How do I know when I've distributed correctly?

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Count your terms! 2(x+4) 2(x+4) should become two terms: 2x+8 2x + 8 . If you only have one term, you forgot to distribute to something!

Why does my answer come out different when I don't distribute properly?

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Because you're solving a different equation! If you write 2x+4+8=0 2x + 4 + 8 = 0 instead of 2x+8+8=0 2x + 8 + 8 = 0 , you get x=6 x = -6 instead of the correct x=8 x = -8 .

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