Solve the Linear Equation: 3(y-2)+2(y+3)=180

3(y2)+2(y+3)=180 3(y-2)+2(y+3)=180

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Open parentheses properly, multiply by each factor
00:14 Collect terms
00:23 Isolate Y
00:34 Break the fraction into two integers and then combine
00:37 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

3(y2)+2(y+3)=180 3(y-2)+2(y+3)=180

2

Step-by-step solution

To solve this equation, we follow these steps:

  • Step 1: Distribute the coefficients within the parentheses.
  • Step 2: Combine like terms.
  • Step 3: Rearrange the equation to isolate and solve for yy.

Let's apply these steps to solve the equation 3(y2)+2(y+3)=1803(y-2)+2(y+3)=180:

Step 1: Distribute the terms:
3(y2)+2(y+3)=3y6+2y+6 3(y-2) + 2(y+3) = 3y - 6 + 2y + 6 .

Step 2: Combine like terms:
Combine the yy terms and the constant terms: 3y+2y6+6=5y3y + 2y - 6 + 6 = 5y.
Thus, the equation simplifies to 5y=1805y = 180.

Step 3: Solve for yy:
To find yy, divide both sides by 5:
5y/5=180/5 5y / 5 = 180 / 5 , which simplifies to y=36y = 36.

Therefore, the solution to the equation is y=36 y = 36 .

3

Final Answer

36

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\( 2(4-x)=8 \)

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