Solve the Linear Equation: Applying Distributive Property in 3(a+1) - 3 = 0

Linear Equations with Distributive Property

3(a+1)3=0 3(a+1)-3=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's solve the problem together.
00:09 First, open the brackets carefully, and multiply each term by the factors inside.
00:17 Next, collect like terms to simplify the expression.
00:29 Then, isolate the variable A on one side of the equation.
00:36 And that's how you find the solution to the problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

3(a+1)3=0 3(a+1)-3=0

2

Step-by-step solution

Let's proceed to solve the linear equation 3(a+1)3=0 3(a+1) - 3 = 0 :

Step 1: Distribute the 3 in the expression 3(a+1) 3(a+1) .

We get:
3a+313=0 3 \cdot a + 3 \cdot 1 - 3 = 0

This simplifies to:
3a+33=0 3a + 3 - 3 = 0

Step 2: Simplify the expression by combining like terms.

We simplify this to:
3a+0=0 3a + 0 = 0 or simply 3a=0 3a = 0

Step 3: Isolate a a by dividing both sides by 3.

3a3=03\frac{3a}{3} = \frac{0}{3}

Thus,
a=0 a = 0

Therefore, the solution to the problem is a=0 a = 0 .

The correct choice is the option corresponding to a=0 a = 0 .

3

Final Answer

a=0 a=0

Key Points to Remember

Essential concepts to master this topic
  • Distributive Rule: Multiply outside term by each term inside parentheses
  • Technique: 3(a+1)=3a+3 3(a+1) = 3a + 3 then combine like terms
  • Check: Substitute a=0 a = 0 : 3(0+1)3=0 3(0+1) - 3 = 0

Common Mistakes

Avoid these frequent errors
  • Not distributing to all terms inside parentheses
    Don't just multiply 3 × a and forget the +1 = 3a3=0 3a - 3 = 0 giving wrong answer! This skips a term and creates an entirely different equation. Always distribute the outside number to every single term inside the parentheses.

Practice Quiz

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\( 5x=1 \)

What is the value of x?

FAQ

Everything you need to know about this question

What does it mean to distribute in math?

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Distribution means multiplying the number outside parentheses by every term inside. Think of it as sharing equally: 3(a+1) 3(a+1) becomes 3×a+3×1 3 \times a + 3 \times 1 .

Why do the +3 and -3 cancel out?

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Because +33=0 +3 - 3 = 0 ! These are like terms (both constants) that combine to zero, leaving us with just 3a=0 3a = 0 .

How do I know when to use the distributive property?

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Look for a number or variable outside parentheses. Whenever you see something like 3(a+1) 3(a+1) or 2(x4) -2(x-4) , you need to distribute first!

What if I get zero as my answer?

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Zero is a perfectly valid answer! Many equations have x=0 x = 0 or a=0 a = 0 as solutions. Always check by substituting back into the original equation.

Can I solve this without distributing?

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You could try other methods, but distributing first is usually the clearest approach. It follows the standard order of operations and helps avoid mistakes.

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