Solve the Logarithmic Equation: n log_x a - Step by Step Guide

Logarithm Power Property with Coefficient Transformation

nlogxa= n\log_xa=

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00:00 Solve
00:03 We will use the power logarithm formula
00:10 We will use this formula in our exercise
00:17 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

nlogxa= n\log_xa=

2

Step-by-step solution

To solve this problem, we need to transform the expression nlogxa n\log_xa using the properties of logarithms.

  • Step 1: Identify the expression: We are given nlogxa n\log_xa , where logxa \log_xa is the logarithm of a a to the base x x , and n n is a coefficient.
  • Step 2: Use the power property of logarithms: The power property of logarithms states that if we have a logarithmic term multiplied by a coefficient n n , like nlogb(a) n\log_b(a) , it can be rewritten as logb(an) \log_b(a^n) .
  • Step 3: Apply the power property: By applying this property to nlogxa n\log_xa , we rewrite it as logx(an) \log_x(a^n) . This is because multiplying the logarithmic term by an external coefficient is equivalent to taking the argument a a to the power of that coefficient, n n .
  • Step 4: Conclusion about the transformation: This transformation demonstrates how the power property helps simplify expressions involving logarithms by turning multiplication into an exponentiation within the logarithm itself.

Therefore, the expression nlogxa n\log_xa can be transformed and expressed as logxan \log_xa^n by using the power property of logarithms.

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Final Answer

logxan \log_xa^n

Key Points to Remember

Essential concepts to master this topic
  • Power Property: Coefficient outside becomes exponent inside the logarithm
  • Technique: Transform nlogxa n\log_x a into logxan \log_x a^n
  • Check: Verify base stays same and argument becomes an a^n

Common Mistakes

Avoid these frequent errors
  • Moving coefficient to the wrong position
    Don't move n to the base like logxna \log_{xn} a or after the argument like logxan \log_x an = completely wrong forms! The coefficient affects only the argument's exponent, not the base or as multiplication. Always move the coefficient n to become the exponent of the argument: logxan \log_x a^n .

Practice Quiz

Test your knowledge with interactive questions

\( \log_75-\log_72= \)

FAQ

Everything you need to know about this question

Why does the coefficient n become an exponent?

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This comes from the power property of logarithms! When you have a number multiplying a log, it's like saying "how many times do I need this logarithm?" which translates to raising the argument to that power.

What happens to the base x when I apply this rule?

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The base stays exactly the same! Only the argument (the number inside the log) changes. So nlogxa n\log_x a becomes logxan \log_x a^n - same base x.

Can I use this property backwards too?

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Absolutely! If you see logxan \log_x a^n , you can write it as nlogxa n\log_x a . This property works both ways and is very useful for simplifying complex logarithmic expressions.

What if n is a fraction like 1/2?

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The same rule applies! 12logxa=logxa1/2=logxa \frac{1}{2}\log_x a = \log_x a^{1/2} = \log_x \sqrt{a} . Fractional exponents work just like whole number exponents in this property.

Does this work with natural logs and common logs too?

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Yes! This power property works with all logarithms: nlna=lnan n\ln a = \ln a^n and nloga=logan n\log a = \log a^n . The base doesn't matter for this rule.

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