Solve the Logarithmic Equation: log₆8 Step by Step

Logarithm Properties with Power Rule

log68= \log_68=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:04 Let's break down 8 to 2 to the power of 3
00:17 Let's use the logarithm of power formula
00:22 Let's use this formula in our exercise
00:28 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log68= \log_68=

2

Step-by-step solution

To solve the problem log68 \log_6 8 , we need to express the number 8 as a power of a base that simplifies the logarithm. We can write 8 as 23 2^3 , because 8 equals 2 multiplied by itself three times.

Let's use the power property of logarithms, which is:

  • logb(an)=nlogba\log_b (a^n) = n \log_b a

Applying this property to log68\log_6 8, we have:

log68=log6(23)\log_6 8 = \log_6 (2^3)

Using the power property, this becomes:

log6(23)=3log62\log_6 (2^3) = 3 \log_6 2

Therefore, the expression for log68\log_6 8 in terms of log62\log_6 2 is:

3log623 \log_6 2.

3

Final Answer

3log62 3\log_62

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: logb(an)=nlogba \log_b(a^n) = n \log_b a brings exponents down
  • Technique: Rewrite 8 as 23 2^3 , then apply power property
  • Check: Verify 63log62=(6log62)3=23=8 6^{3\log_6 2} = (6^{\log_6 2})^3 = 2^3 = 8

Common Mistakes

Avoid these frequent errors
  • Trying to simplify logarithms without using properties
    Don't attempt to calculate log68 \log_6 8 directly as a decimal = messy approximations! This misses the exact algebraic form. Always look for ways to express the argument as a power first, then apply logarithm properties.

Practice Quiz

Test your knowledge with interactive questions

\( \log_{10}3+\log_{10}4= \)

FAQ

Everything you need to know about this question

Why can't I just calculate log₆8 with a calculator?

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While calculators give decimal approximations, the question asks for an exact algebraic expression. The answer 3log62 3\log_6 2 is more precise and shows the mathematical relationship.

How do I know to write 8 as 2³?

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Look for perfect powers of small integers! Since 8 = 2×2×2, we write it as 23 2^3 . This makes the power rule applicable and simplifies the expression.

What if the base and argument don't seem related?

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Don't worry about connecting base 6 and argument 8 directly. The key is expressing 8 as a power of any convenient number, then using logarithm properties to simplify.

Can I use other logarithm properties here?

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The power rule is the most useful here since 8 is a perfect cube. Other properties like product or quotient rules would make this problem more complicated.

How do I verify this answer makes sense?

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Remember that log68 \log_6 8 asks "what power of 6 gives 8?" Since 63log62=(6log62)3=23=8 6^{3\log_6 2} = (6^{\log_6 2})^3 = 2^3 = 8 , our answer works!

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