Simplify the Expression: log₉(e²)/log₉(e) Using Log Properties

log9e2log9e= \frac{\log_9e^2}{\log_9e}=

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Step-by-step video solution

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00:00 Solve
00:03 We'll use the formula for logarithmic division
00:08 We'll get the logarithm of the numerator with the denominator as the base
00:13 We'll use this formula in our exercise
00:23 We'll use the formula for logarithm of a power
00:28 We'll use this formula in our exercise
00:40 The logarithm of any number in its own base is always equal to 1
00:53 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log9e2log9e= \frac{\log_9e^2}{\log_9e}=

2

Step-by-step solution

To solve this problem, we'll simplify the given expression log9e2log9e\frac{\log_9e^2}{\log_9e} using logarithmic rules:

Step 1: Apply the power rule of logarithms:
The numerator log9e2\log_9e^2 can be rewritten using the power rule: log9e2=2log9e\log_9e^2 = 2 \cdot \log_9e.

Step 2: Substitute and simplify the fraction:
Substitute the expression from Step 1 into the original problem:
log9e2log9e=2log9elog9e\frac{\log_9e^2}{\log_9e} = \frac{2 \cdot \log_9e}{\log_9e}.

Step 3: Cancel common terms:
Since log9e\log_9e appears in both the numerator and the denominator, it cancels out, leaving:
2log9elog9e=2 \frac{2 \cdot \log_9e}{\log_9e} = 2 .

Therefore, the solution to the problem is 2\boxed{2}.

3

Final Answer

2 2

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\( \frac{1}{\log_49}= \)

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